Simply the Expression.<br>

Precalc question: a warhead fired from an enemy ship in the persian gulf is a dud and only travels 100 meters before it hits the

soldi70 [24.7K]

Answer:

0.2s is the time from the initial launch of the warhead to impact.

Step-by-step explanation:

This is a rule of three problem

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, our measures have a direct relationship.

The problem states that in a second, the warhead travels 489 meters. How long it takes to travel 100 meters? So

1s - 489m

xs - 100m

489x = 100

$x = \frac{100}{489}$

x = 0.2s.

0.2s is the time from the initial launch of the warhead to impact.

3 0

3 years ago

An elevator has a placard stating that the maximum capacity is 1296 lb long dash — 8 passengers. So, 8 adult male passengers ca

Masja [62]

Answer:

There is a 98.26% probability that it is overloaded.

This elevator does not appear to be safe.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of males are normally distributed with a mean of 170 lb, so $\mu = 170$

They have a standard deviation of standard deviation of 29 lb, so $\sigma = 29$ .

We have a sample of 8 adults, so we have to find the standard deviation of the sample to use in the place of $\sigma$ in the Z score formula.

$s = \frac{\sigma}{8} = \frac{29}{8} = 3.625$

Find the probability that it is overloaded because they have a mean weight greater than 162 lb, so $X = 162$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{162 - 170}{3.625}$

$Z = -2.21$

$Z = -2.21$ has a pvalue 0.0174.

So, there is a 1-0.0174 = 0.9826 = 98.26% probability that it is overloaded.

Any probability that is above 95% is considerer unusually high. So, this elevator does not appear to be safe, since there is a 98.26% probability that it is overloaded.

8 0

3 years ago

Suppose that the local sale tax rate is 4% and you purchase a car for $17,000.

lapo4ka [179]

A. $680 tax is paid
B. The total cost is $17,680

4 0

3 years ago

Finding missing angle. PLEASE HELP ME!

pishuonlain [190]

Answer:

x=147°

Step-by-step explanation:

1. Analyze: The angle opposite to the 33 degree angle is 33 degrees because they are vertical angles.

2. Make an equation: The sum of all four angles (x, the angle opposite of x, the 33 degree angle, and the angle opposite of the 33 degree angle) is 360°. Therefore the equation would be (33°x2)+2x= 360°.

3. Solve for x:

a. Multiply 33 by 2

66+2x=360

b. Subtract 66 from both sides

66+2x=360

-66 -66

2x=294

c. Divide both sides by 2

$\frac{2x}{2} =\frac{294}{2}$

x=147

4. Remember to add your label- the degree sign (°)

x=147°

4 0

3 years ago

in a certain normal distribution, 6.3% of the area lies to the left of 36 and 6.3% of the area lies to the right of 42. Find the

KATRIN_1 [288]

As the normal distribution is symmetric the mean is (36 + 42) / 2 = 39

p(X < 42) = 1 - 0.063 = 0.937

From tables Φ (1.53) = 0.9370

From this time:

42 is 1.53 standard deviations above the mean

42 = 39 + 1.53s

1.53s = 3

Standard deviation is = 1.96

5 0

3 years ago

Simply the Expression.​

Simply the Expression.