(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

which reduces to
<em>c</em> / 2 (0 + 1) = 1 → <em>c</em> = 2
(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

A= l•w
So you can make it in any way! The one I got is 44•4 because
A= l•w
A= 4•22
A= 88
So I guess it depends on the way you want it as long as it equals 88 as long as you length and width are multiplied to make the 88, if you host what I mean!
Answer:
j = 10
Step-by-step explanation:
You add 7 to both sides then divide both sides by -2
The range is: 35-60
The IQR is: 11
This value is the first 25%
IQR= interquartile range
Hope this helps ;)