Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
function
Step-by-step explanation:
Answer: standard deviation
Step-by-step explanation:
Hey dude we’re both from Nepal so here’s the written worksheet hope it helps :)
The probability that the spinner lands on an even number or on the unshaded section is; 3/5
<h3>How to find the probability?</h3>
From the spinner attached, we see that the number of sections on the spinner is 5 sections.
Now, we can also see that;
Number of even numbers section = 2
Number of shaded sections = 1
Thus, probability that the spinner lands on an even number or on the unshaded section is;
P(even number or unshaded section) = (2 + 1)/5 = 3/5
Read more about Probability at; brainly.com/question/24756209
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