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ozzi
2 years ago
7

OXIDATION ELECTRON TRANSFER

Chemistry
1 answer:
AfilCa [17]2 years ago
5 0

Answer:

Loss of electrons

Explanation:

Oxidation occurs in a redox reaction where electrons are transferred from one reactant to another.

  • The loss of electrons is called oxidation.
  • The gaining of electrons is called reduction.
  • The reactant that causes oxidation is called the oxidizing agent
  • The reactant that causes reduction is called the reduction agent
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You have to make 500 mL of a 1.50 M BaCl2. You have 2.0 M barium chloride solution available. Determine how to make the needed d
Inga [223]

Answer:

You need 375 mL of BaCl2 solution.

Explanation:

M1V1=M2V2

Dilution formula. Substitute known values and solve for V1.

M1 = 2.0 M

M2 = 1.50 M

V2 = 500 mL

(2.0 M)(V1) = (1.50 M)(500 mL)

V1 = (1.50 M)(500 mL) / (2.0 M)

V1 = 375 mL

7 0
3 years ago
Is 334mm bigger than 1 km
Levart [38]

Answer:

no km are bigger

Explanation:than mm

5 0
3 years ago
A jar is filled to the top with water, and a piece of cardboard is slid over the opening so that there is only water in the . If
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it will all fall unless these is air

Explanation:

7 0
3 years ago
Read 2 more answers
Which statements are true of the reaction below? 2na(s) + cl2(g) 2nacl(s) Check all that apply. A - NaCl is a product B - Na(s)
Bumek [7]

Answer:

A - NaCl is a product

D - Cl2 is a gas

Explanation:

Based on the chemical reaction;

2Na(s) + Cl2(g) → 2NaCl2

  • Sodium metal reacts with chlorine gas to form sodium chloride. Sodium is in solid state, chlorine is in gaseous state and Sodium chloride is in solid state.
  • In the chemical reaction, sodium and chlorine are reactants while sodium chloride is the product.
  • Additionally the chemical reaction above is balanced so as to obey the law of conservation of mass.
4 0
3 years ago
If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
3 years ago
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