Answer:
The ideal molar volume is 
The Z factor is 
The real molar volume is 
Explanation:
From the question we are told that
The pressure is 
The temperature is 
According to the ideal gas equation we have that
=> 
Where 
is the molar volume and R is the gas constant with value
substituting values
The compressibility factor of the gas is mathematically represented as
substituting values
Now the real molar volume is evaluated as
substituting values
Answer:
Explanation:
Mixture: is combination of one or more substances mix together.
• The properties of the mixture are not same and contains the properties of all those component present in it.
• it is a combination of one or more Pure substances and can be separated by simple physical methods.
• it have varying boiling and melting point
Homogeneous Mixture: are those which are not distinguish by naked eye but can be separated into its components by physical means.
The components of a homogeneous mixture are in the same phase oar in dissolved form so it look like one component.
Examples are:
• Salt water is mixture of water and NaCl and can be separated by physical mean.
• Air: mixture of gases
Heterogeneous mixture: are those which can be distinguishing by naked eye and can be separated into its components by physical means.
The component of heterogeneous mixture not fully mixed are different in color or different in phases or not soluble. So one can easily see the difference in the component of the mixture
Examples is
• mixture of salt and sand
• mixture of water and sand
Answer:- Mass of the titanium alloy is 7.01 g, choice C is correct.
Solution:- The heat of fusion is given as 422.5 joules per gram and it also says that 2960 joules of heat is required to melt the metal completely.
The suggested equation is, 
where Q is the heat energy, m is the mass and Hf is the heat of fusion.
Since, we are asked to calculate the mass, the equation could be written as:
Let's plug in the values in it:
m = 7.01 g
So, the mass of the titanium alloy is 7.01 g, choice C is correct.
The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below
the heat of vaporization of acetone at its boiling point is 29.1 kj/mole
find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles
heat (Q) = moles x heat of vaporization
= 29.1 kj/mole x 0.757 moles = 22.03 kj
