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tekilochka [14]
3 years ago
13

What is log of 52????

Chemistry
2 answers:
irinina [24]3 years ago
8 0

1.71600334       Hope Im right                

erik [133]3 years ago
3 0
1.716003344 <--- this the log of 52!
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Consider two equal-volume flasks of gas at the same temperature and pressure. One gas, oxygen, has a molecular mass of 32. The o
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Answer: The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

Explanation:

According to avogadro's law, equal volumes of all gases at same temperature and pressure have equal number of moles.

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus as oxygen and nitrogen are at same temperature and pressure and are in equal volume flasks , they have same number of moles and thus have same number of molecules.

The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

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Imagine a made-up pol
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Answer:

No change to the cation  Add -ide to the anion

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Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the temperature of the water. The wat
Alex777 [14]

Answer:

The boiling point decreases as the volume decreases.

Explanation:

The Temperature - Volume law otherwise called as Charles law is applied, which says that the volume of the given gas at constant pressure is directly proportional to the temperature measured in Kelvin. As the volume increases, the temperature also increases, if the volume decreases, then the temperature also decreases.

As per the Charles law, here the volume is decreased from 50 ml to 25 ml so the boiling point also decreases.

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3 years ago
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10.
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The best answer is:

a. Extrusive igneous rocks

In general, rocks that are formed by the cooling of magma are classified as igneous rocks. The key word however in this case is "lava," which is magma that reached the surface. This is what makes it an extrusive igneous rock, because it formed in the surface.

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2.122 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/
aleksandr82 [10.1K]

Answer:

The weight percent of potassium carbonate is 50,8 wt% and of potassium bicarbonate 49,2 wt%

Explanation:

The reactions of potassium carbonate (K₂CO₃) and potassium bicarbonate (KHCO₃) with HCl produce:

K₂CO₃ + 2HCl → 2KCl + CO₂ + H₂O

KHCO₃ + HCl → KCl + CO₂ + H₂O

That means that you need 2 moles of HCl to titrate potassium carbonate and 1 mol to titrate potassium bicarbonate.

The moles of HCl to titrate the mixture are:

0,03416L×\frac{0,762mol}{1L} = <em>0,02603 mol of HCl</em>

If X is mass of K₂CO₃ and Y is mass of KHCO₃ in the mixture, the moles of HCl to titrate the mixture are equals to:

0,02603 mol = 2X×\frac{138,2058 g}{1mol} + Y×\frac{100,1154 g}{1mol} <em>(1)</em>

As the mass of the mixture is 2,122g:

2,122g = X + Y <em>(2)</em>

Replacing (2) in (1):

0,02603 mol = 0,01447 (2,122-Y) + 9,988x10⁻³Y

0,02603 mol = 0,0307 - 0,01447Y + 9,988x10⁻³Y

-4,6778x10⁻³ = -4,4827x10⁻³Y

1,044g = Y <em>-mass of potassium bicarbonate-</em>

Thus:

X = 1,078g <em>-mass of potassium carbonate-</em>

The weight percent of potassium carbonate is:

\frac{1,078g}{2,122g}×100 =<em> 50,8 wt%</em>

The weight percent of potassium bicarbonate is:

\frac{1,044g}{2,122g}×100 = <em>49,2 wt%</em>

<em></em>

I hope it helps!

5 0
3 years ago
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