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schepotkina [342]
2 years ago
9

!Urgent!

Chemistry
1 answer:
kogti [31]2 years ago
6 0

This question was already answered here's the link

brainly.com/question/2023746

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What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?
Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0
3 years ago
Explain why elements with less protons require fewer neutrons to be stable compared to elements with more protons.​
Solnce55 [7]

Answer:

The reason for this is because of the repulsive force between protons: The stronger the repulsion force, the more neutrons are needed to stabilize the nuclei.

Explanation:

7 0
3 years ago
What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?
sashaice [31]

Answer:

\boxed {\boxed {\sf PCl_3}}

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

  • 22.5 g P
  • 77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

  • P: 30.974 g/mol
  • Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. 22.5 \ g \ P  * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P

77.5 \ g \ Cl  * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl

Divide both of the moles by the smallest number of moles to find the mole ratio.

\frac {0.7264157035} {0.7264157035} = 1

\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>

4 0
3 years ago
Write the TOTAL IONIC EQUATION between zinc and hydrochloric acid.
Andreyy89

Answer : The net ionic equation will be,

Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced ionic equation between zinc and hydrochloric acid will be,

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

The ionic equation in separated aqueous solution will be,

Zn(s)+2H^+(aq)+2Cl^-(aq)\rightarrow Zn^{2+}(aq)+2Cl^-(aq)+H_2(g)

In this equation, Cl^- is the spectator ion.

By removing the spectator ion from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)

8 0
3 years ago
Show calculations for determining the mass of sugar in an 8 oz sample of soft drinks.​
poizon [28]

Answer:

m_{sugar}=23.7g\ sugar

Explanation:

Hello,

In this case, we can first compute the volume of the sample in mL from the ounces:

8oz*\frac{29.5735mL}{1oz} =236.6mL

Thus, with the volume of the sample, we can compute the amount of sugar given the 10 g of sugar per 100 mL of soft drink as shown below:

m_{sugar}=236.6mL*\frac{10g\ sugar}{100mL}\\ \\m_{sugar}=23.7g\ sugar

Best regards.

7 0
3 years ago
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