Answer:
500 N
Explanation:
Natural bouyency will keep the diver in the same place, no matter what the mass of gfs. This means if the diver is displacing with a weight of 500 N, the upthrust will also be 500 N.
Answer:
94.67 N
Explanation:
Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.
At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.

Substituting 70 N for W, 41 N for F and
for 37 degrees
N=70+41sin37=94.67441595 N and rounding off to 2 decimal places
N=94.67 N
Answer:
500J
Explanation:
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Ok. PEMDAS tells us to take care of the square first. When we do that, the denominator becomes
(6.4)^2 x 10^12
= 40.96 x 10^12 .
Now it's just a matter of mashing out the fraction.
The 'mantissa' (the number part) is
6/40.96 = 0.1465
and the order of magnitude is
10^24 / 10^12 = 10^12 .
Put it all together and you've got
1.465 x 10^11 .
Answer:
33.6371 m
Explanation:
t = Time taken
u = Initial velocity = 20.3 m/s
v = Final velocity
s = Displacement
a = Acceleration = -7 m/s²
Distance traveled in the 0.207 seconds
Distance = Speed × Time
⇒Distance = 20.3×0.207 = 4.2021 m
Equation of motion

Distance traveled by the car while braking is 29.435 m
Total distance measured from the point where the driver first notices the red light is 29.435+4.2021 = 33.6371 m