Answer:
Force on front axle = 6392.85 N
Force on rear axle = 8616.45 N
Explanation:
As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels
Now we know that



now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle
so we can write torque balance about its center of mass


now from above equation

now we have

now the other force is given as

Answer:
16 m/s.
Explanation:
The following data were obtained from the question:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Mass of car = 2500 kg
Velocity of car =..?
Next, we shall determine the momentum of the truck. This can be obtained as follow:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Momentum of truck =.?
Momentum = mass × velocity
Momentum = 5000 × 8
Momentum of the truck = 40000 Kg.m/s
Finally, we shall determine the velocity of the car as follow:
From the question given above, we were told that the car and truck has the same momentum.
This implies that:
Momentum of the truck = momentum of car = 40000 Kg.m/s
Thus, the velocity of the car can be obtained as shown below:
Mass of car = 2500 kg
Momentum of the car = 40000 Kg.m/s
Velocity of car =..?
Momentum = mass × velocity
40000 = 2500 × velocity
Divide both side by 2500
Velocity = 40000/2500
Velocity = 16 m/s
Therefore, the velocity of the car is 16 m/s.