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4 years ago

Describe briefly difference between conduction, convection, and radiation.

Physics

1 answer:

Fed [463]4 years ago

3 0

The three types of heat transfer are conduction convection and radiation. <u>Explanation:</u>

Heat transfer happens only when there is said to be a temperature difference. (i.e) heat transfer occurs with a higher temperature region to a lower temperature region.
Heat is transferred usually via some medium in the case of convection and conduction whereas in the radiation no medium is required ( i.e it take place in a vacuum ).
Conduction is a type of heat transfer that is mainly a character for the conducting and semiconducting solid material.
Convection is the heat transfer method that usually takes place in the liquids and gases.
Radiation is the heat transfer process in which heat is transferred via infrared or electromagnetic waves.

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4 years ago

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Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

$q=m\times c\times (T_2-T_1)$

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = $4.18J/g.K$

$T_1$ = initial temperature of water = 293.0 K

$T_2$ = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

$q=250g\times 4.18J/g.K\times (371.2-293.0)K$

$q=81719J$

Now we have to calculate the enthalpy of combustion of octane.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

$\Delta H=\frac{-81719J}{0.015mole}$

$\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol$

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

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4 years ago

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The pressure at the bottom of a column of fluid in a container
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