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3 years ago

What is it asking MathPhys im sorry i dont know but i tried teaching myself physics but i cant

Physics

1 answer:

RSB [31]3 years ago

6 0

Answer:

The puck B remains at the point of collision.

Explanation:

This is an elastic collision, so both momentum and energy are conserved.

The mass of both pucks is m.

The velocity of puck B before the collision is vb.

The velocity of puck A and B after the collision is va' and vb', respectively.

Momentum before = momentum after

m vb = m vb' + m va'

vb = vb' + va'

Energy before = energy after

½ m vb² = ½ m vb'² + ½ m va'²

vb² = vb'² + va'²

Substituting:

(vb' + va')² = vb'² + va'²

vb'² + 2 va' vb' + va'² = vb'² + va'²

2 va' vb' = 0

va' vb' = 0

We know that va' isn't 0, so:

vb' = 0

The puck B remains at the point of collision.

You might be interested in

If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What

Pavel [41]

Answer: $1.54m^3$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas at STP = 1 atm

$P_2$ = final pressure of gas = 2.67 atm

$V_1$ = initial volume of gas = $3.61m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas at STP = $0^oC=273+0=273K$

$T_2$ = final temperature of gas = $37.9^oC=273+37.9=310.9K$

Now put all the given values in the above equation, we get:

$\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}$

$V_2=1.54m^3$

Thus the final volume will be $1.54m^3$

7 0

3 years ago

Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di

Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, $u=20m/s$

And the mass of the car is, $m=1000 kg$

The total distance covered by the car before stop, $s=45m$

And the final speed of the car is, $u=0m/s$

Now initial kinetic energy is,

$KE_{i}=\frac{1}{2}mu^{2}$

Substitute the value of u and m in the above equation, we get

$KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J$

Now final kinetic energy is,

$KE_{f}=\frac{1}{2}mv^{2}$

Substitute the value of v and m in the above equation, we get

$KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J$

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

$F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN$

Here, the force is negative because the force and acceleration in the opposite direction.

6 0

3 years ago

Intrapulmonary pressure is the _______________________.

lisabon 2012 [21]

Intrapulmonary pressure is the pressure within the lungs

4 0

3 years ago

Find the Cartesian components of force PP acting in the x, y, and z directions given P=50.0 NP=50.0 N, α=143.5∘α=143.5∘, β= 70.0

BlackZzzverrR [31]

Answer:

vec(F) = [ -40.193 i + 17.101 j + 24.317 k ]

Explanation:

Given:

-The force P = 50.0 N

- Angle with x-axis α = 143.5

- Angle with y-axis β = 70.0

- Angle with z-axis γ = 60.9

Find:

Find the Cartesian components of force P acting in the x, y, and z directions,

Solution:

- The Force vector in the Cartesian coordinate system is given by the dot product of the Force P and the unit vector in its direction.

F.unit(u) = vec(F)

- Where, the unit vector is defined as:

unit (u) = [ cos(α) i + cos(β) j + cos(γ) k ]

- Using the given unit angles α , β, and γ compute unit (u):

unit (u) = [ cos(143.5) i + cos(70) j + cos(60.9) k ]

unit (u) = [ -0.80386 i + 0.34202 j + 0.48634 k ]

- The force vector is:

vec(F) = 50.[ -0.80386 i + 0.34202 j + 0.48634 k ]

vec(F) = [ -40.193 i + 17.101 j + 24.317 k ]

4 0

3 years ago

Por favoooor, necesito ayudaa con estos ejercicios de fisica:((

cluponka [151]

Answer:

a) distance = 15340 km

b) time = 3437 seconds

c) velocity = 2.16 km/h

Explanation:

a) If the plane's speed is 295 km/m and it takes 52 minutes to get to its destination, then we can calculate the distance travelled via the distance formula:

Distance = v * t

and since the time units are both the same in the quantities to multiply (km/minute and minutes travelled), then they cancel out and the distance results in Km:

Distance = 295 * 52 = 15340 km

b) For this problem we need to convert Hm (hectometers) into meters in order to be able to simplify the units appropriately when using the distance formula.

recall that 1 Hm - 100 meters, then 3265 Hm = 326500 m

Distance = v * t

326500 = 95 * t

solving for "t":

t = 326500 / 95

t = 3437 seconds

c) In this problem, we need to convert the distance from m to km, and the time from min into hours in order to give the answer in the requested units. We also use the distance formula we have been using so far,

936 m = 0.936 km

26 min = 26/60 h

Then the magnitude of the velocity becomes:

v = Distance / time = 0.936 / (26/60) ≈ 2.16 km/h

4 0

3 years ago