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stealth61 [152]
3 years ago
15

What term describes the resistance that one encounters when moving over another

Physics
1 answer:
Anvisha [2.4K]3 years ago
5 0
Friction? For example, like when a car's tires skid on rough concrete.
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Two passenger trains are passing each other on adjacent tracks. train a is moving east with a speed of 13 m/s, and train b is tr
alukav5142 [94]

Since the two trains are passing in opposite directions, so this means that their relative velocities will be the sum of the two trains that is: 

<span>
relative velocity = (13 + 28) = 41m/s</span>

<span>
a. The passengers aboard on train B will see that train A is moving at 41m/sec due east</span>

 

<span>b. The passengers aboard on train A will see that train B is moving at 41m/sec due west</span>

7 0
3 years ago
Read 2 more answers
When mass m is tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is 180 h
Katena32 [7]
The frequency of the nth-harmonic of a string is given by
f_n =  \frac{n}{2L}  \sqrt{ \frac{T}{\mu} }
where n is the number of the harmonic, L is the length of the string, T the tension and \mu the linear density. 

In our problem, since the mass m is tied to the string, the tension is equal to the weight of the object tied:
T=mg
Substituting into the first formula, we have
f_n =  \frac{n}{2L}  \sqrt{ \frac{mg}{\mu} }

In our problem we have n=2 (second harmonic). In the previous equation, the only factor which is not constant between the first and the second part of the problem is m, the mass. So, we can rewrite everything as
f_2 = K  \sqrt{m}
where we called 
K= \frac{2}{2L}  \sqrt{ \frac{g}{\mu} }

In the first part of the problem, the mass of the object is m and f_2 = 180 Hz. So we can write 
180 Hz = K  \sqrt{m}

When the mass is increased with an additional 1.2 kg, the relationship becomes
270 Hz = K \sqrt{(m+1.2 Kg)}

By writing K in terms of m in the first equation, and subsituting into the second one, we get
180 Hz  \sqrt{ \frac{m+1.2 Kg}{m} }=270 Hz
and solving this, we find
m=0.96 kg


5 0
3 years ago
A 58 kg boy and a 38 kg girl use an elastic rope while engaged in a tug-of-war on a frictionless icy surface. If the acceleratio
Arada [10]
H rerrr hrdzjrtfhhtthfjytr
6 0
3 years ago
Someone help please ?
kap26 [50]
The first box is #3
the second box is #1
the third box is #2
the way I found this out because i read the definitions and found the key words in there.
7 0
3 years ago
Find the volume of a box with length 25 cm, height 25 cm and width 1.0 m.
emmasim [6.3K]
Before finding the volume, it is always good to change the units as same.
length 25cm
height 25cm
width 100cm

volume
length * height * width
25 * 25 * 100
62500 cm^3
5 0
3 years ago
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