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2 years ago

Can I get help with question 6-9

Mathematics

1 answer:

seropon [69]2 years ago

8 0

Answer:

Step-by-step explanation:

6)For question 6 you have the right idea but as the new image is bigger than the pre-image the scale factor would be 3/1

7)You have the right answer but the fraction can be simplified to 2

8)I think this question is asking for the angle in the triangle on the left that is the same as the one on the right so from left to right,

F=R G=S H=T

FG=RS GH=ST FH=RT

9)The scale facto for the longest edge here is 2 but the scale factor for the shortest edge is 18/8 which is equal to 9/4 so the are not congruent as they have two different scale factors. Answer) no

10) the triangles are similar as angle a=n and 55+35+90 = 180 so yes they are similar

Hope this helps :)

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Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total s

garri49 [273]

Answer

a. The expected total service time for customers = 70 minutes

b. The variance for the total service time = 700 minutes

c. It is not likely that the total service time will exceed 2.5 hours

Step-by-step explanation:

This question is incomplete. I will give the complete version below and proceed with my solution.

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total service time for customers arriving during a 1-hour period. (Assume that a sufficient number of servers are available so that no customer must wait for service.) Is it likely that the total service time will exceed 2.5 hours?

Reference

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour.

From the information supplied, we denote that

$X=$ Customers that arrive within the hour

and since $X$ follows a Poisson distribution with mean $\alpha$ = 7

Therefore,

$E(X)= 7$

$& V(X)=7$

Let $Y =$ the total service time for customers arriving during the 1 hour period.

Now, since it takes approximately ten minutes to serve each customer,

$Y=10X$

For a random variable $X$ and a constant $c$ ,

$E(cX)=cE(X)\\V(cX)=c^2V(X)$

Thus,

$E(Y)=E(10X)=10E(X)=10*7=70\\V(Y)=V(10X)=100V(X)=100*7=700$

Therefore the expected total service time for customers = 70 minutes

and the variance for serving time = 700 minutes

Also, the probability of the distribution $Y$ is,

$p_Y(y)=p_x(\frac{y}{10} )\frac{dx}{dy} =\frac{\alpha^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-\alpha } \frac{1}{10}\\ =\frac{7^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-7 } \frac{1}{10}$

So the probability that the total service time exceeds 2.5 hrs or 150 minutes is,

$P(Y>150)=\sum^{\infty}_{k=150} {p_Y} (k) =\sum^{\infty}_{k=150} \frac{7^{\frac{k}{10} }}{(\frac{k}{10})! }.e^{-7} .\frac{1}{10} \\=\frac{7^{\frac{150}{10} }}{(\frac{150}{10})! } .e^{-7}.\frac{1}{10} =0.002$

0.002 is small enough, and the function $\frac{7^{\frac{k}{10} }}{(\frac{k}{10} )!} .e^{-7}.\frac{1}{10}$ gets even smaller when $k$ increases. Hence the probability that the total service time exceeds 2.5 hours is not likely to happen.

3 0

2 years ago

Please help with this problem!

Dovator [93]

Answer:

x+14

Step-by-step explanation:

(12+x)+2

12+x+2

x+(12+2)

x+14

4 0

3 years ago

Read 2 more answers

a storage jug was 4/5 full of water when did get indicated 72 what was the full capacity of the storage jug

IRISSAK [1]

Answer:

90. ( was the full capacity of jug)

to solve this 

firstly let the full capacity of jug 

 

be. x

so, 

4/5*x = 72

x = 72*5/4

x = 90

hope it helps

6 0

2 years ago

To the nearest dollar, what does the analyst believe

ruslelena [56]

The analyst believes the value of the stock at the end of three weeks will be $134.

<h3>What are stocks?</h3>

Stock (also known as capital stock) in finance refers to the shares of ownership in a corporation or company.
A single share of stock represents fractional ownership of the corporation based on the total number of shares.
This typically entitles the shareholder (stockholder) to that fraction of the company's earnings, proceeds from asset liquidation (after discharge of all senior claims such as secured and unsecured debt), or voting power, which are often divided in proportion to the amount of money invested by each stockholder.

To find the value of the stock:

Because the stock price drops by 28% every week, it will be:
100 - 28 = 72% every week.
So, r = 0.72.
Then, the equation V = 360(r)∧t will be V = 360(0.72)∧t .
After 3 weeks, V = 360(0.72)³ = 134.47 = 134

Therefore, the analyst believes the value of the stock at the end of three weeks will be $134.

Know more about stocks here:

brainly.com/question/690070

#SPJ4

The correct question is given below:

To the nearest dollar, what does the analyst believe the value of the stock will be at the end of three weeks? (Note: Disregard the $ sign when gridding your answer.)

3 0

1 year ago

Is this a function ?

Goshia [24]

I don’t think so, a graph is a function only if the vertical line passes through the graph at one distinct point.

But I’m not exactly sure cus I’m still learning geogebra

6 0

2 years ago