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3 years ago

14−yi=14+12i what does y equal

Mathematics

1 answer:

White raven [17]3 years ago

5 0

Answer:

y=-12

Step-by-step explanation:

Step 1: Add -14 to both sides.

Step 2: Divide both sides by -i.

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In 1 hr, a plane can travel 440 mi into the wind and 480 mi with the wind. Find the wind speed and the rate of the plane in stil

nexus9112 [7]

Answer:

the plane would fall and crash at 150mph

Step-by-step explanation:

8 0

3 years ago

TRUE OR FALSE: FOR ANY FUNCTION, X=F^-1(Y), THEN Y=F(X). PLEASE EXPLAIN

Vesnalui [34]

Answer:

True.

Step-by-step explanation:

For example let f(x) = 3x + 1 then f-1(x) is found as follows

Let f(x) = y = 3x + 1 then

3x = y - 1

x = (y-1) / 3

x = f-1(x) = (x - 1)/3.

So:

Replacing the x in y by (x - 1)/3 :-

x = f(-1)(y) = ( (3x + 1) - 1) / 3

= 3x / 3

= x.

So y = f(x).

7 0

3 years ago

Please help! Brainliest if you explain

My name is Ann [436]

Switch sides

4/5 (x+3)=y+6

Multiply both sides by 5

5*4/5 (x+3) = 5y+5*6

Simplify

4(x+3) = 57+30

Divide both sides by 4

4(x+3)/4 = 5y/4+ 30/4

Simplify

x+3 = 5y+30/4

Subtract 3 from both sides

x+3 - 3 = 5y+30/4 - 3

Simplify

x=5y+30/4 - 3

3 0

3 years ago

3,053/2,8 Alguien me ayuda porfavor? Pero con el proceso porfa

PtichkaEL [24]

Answer:

1.09

Step-by-step explanation:

Check the photo

6 0

3 years ago

Mystery Boxes: Breakout Rooms

ollegr [7]

Answer:

$\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}$

Required

Fill in the box

From the question, the range is:

$Range = 60$

Range is calculated as:

$Range = Highest - Least$

From the box, we have:

$Least = 1$

So:

$60 = Highest - 1$

$Highest = 60 +1$

$Highest = 61$

The box, becomes:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

From the question:

$IQR = 20$ --- interquartile range

This is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is the median of the upper half while $Q_1$ is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}$

Upper half

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

The quartile is calculated by calculating the median for each of the above halves is calculated as:

$Median = \frac{N + 1}{2}th$

Where N = 7

So, we have:

$Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th$

So,

$Q_3$ = 4th item of the upper halves

$Q_1$ = 4th item of the lower halves

From the upper halves

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

We have:

$Q_3 = 32$

$Q_1$ can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

$IQR = Q_3 - Q_1$

Where $Q_3 = 32$ and $IQR = 20$

So:

$20 = 32 - Q_1$

$Q_1 = 32 - 20$

$Q_1 = 12$

So, the lower half becomes:

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}$

From this, the updated values of the box is:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$