An ideal gas has a volume of 5.00L under a pressure of 1.00 atm and a temperature of 10.0 K. If the temperature is changed to 10
0.0 K while the pressure is increased to 8.00 atm what would be the new volume of the gas?
6.25L
1.60L
400.0L
16.0L
6.25L
1.60L
400.0L
16.0L
1 answer:
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Answer:
7.7439×10⁻³¹ m
Explanation:
The expression for Heisenberg uncertainty principle is:
Where m is the mass of the microscopic particle
h is the Planks constant
Δx is the uncertainty in the position
Δv is the uncertainty in the velocity
Given:
mass = 0.68 g = 0.68×10⁻³ kg
Δv = 0.1 m/s
Δx= ?
Applying the above formula as:
<u>Δx = 7.7439×10⁻³¹ m</u>