Answer:
Explanation:
Given that,
The length of tension wire is 10m
L = 10m
It caries a current of 10A
I = 10A
The current is perpendicular to the magnetic field
B = 5.5 × x10⁻⁵ T.
Then, θ = 90°
The magnetic force that act on the line is?
F = i(L × B)
L × B = LB Sinθ
Where
I is the current
L is the length of the wire
B is the magnetic field
θ is the angle between the field and the direction of the length.
Then,
F = I × L × B × Sinθ
F = 10 × 10 × 5.5 × x10⁻⁵ × Sin 90
F = 5.5 × x10⁻³ N
Then, the magnetic force experience on the line is 5.5 × x10⁻³N
Answer:
distance = 21.56 m
Explanation:
given data
mass = 50 kg
initial velocity = 18.2 m/s
force = -200 N ( here force applied to opposite direction )
final velocity = 12.6 m/s
solution
we know here acceleration will be as
acceleration a = force ÷ mass
a = = -4 m/s²
we get here now required time that is
required time = ...............1
put here value
required time =
so distance will be
distance = ........2
distance =
distance = 21.56 m
Answer:
1. increase
Explanation:
Mass is proportional to gravity. The bigger two objects are, the stronger the force of gravity between them will be.
Answer:
C. A normal distribution displays the highest data scores in the middle of the distribution.
Explanation:
The statement about a normal distribution that is not true is "a normal distribution displays the highest data scores in the middle of the distribution."
Answer: t=4.6*R*L
Explanation: In order to explain this problem we have to take into account the expression for the current in a RL electric circuit, which is given by:
where If is the final current for RL circuit If (emf/R)
Considering the final current is getting when I(t) = 0.99*If we have:
reoganising the terms we have:
e^(-t/R*L)=(1-0.99)
ln(e^(-t/R*L))=ln(0.01)
then t=4.6*R*L