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3 years ago

Motion.

Physics

2 answers:

andrew11 [14]3 years ago

4 0

The answer is D projectile

WINSTONCH [101]3 years ago

4 0

The motion of a ball thrown at an angle is projectile motion.

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Can someone help me asap this is due at 2 50

Rom4ik [11]

The data is inadequate

8 0

3 years ago

Is carbon a metal, nonmetal, or semi-metal

Vlada [557]

Answer: Non metal.

Explanation: Carbon has 4 electrons in it’s valence shell which makes it a metalloid but commonly it is considered as a non metal.

5 0

3 years ago

A bicycle racer inflates their tires to 7.1 atm on a warm autumn afternoon when temperatures reached 27 °C. By morning the tempe

natulia [17]

Answer:

The required pressure is 6.4866 atm.

Explanation:

The given data : -

In the afternoon.

Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa

Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K

In the morning .

Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K

Given that volume remains constant.

To find final pressure ( p₂ ).

Applying the ideal gas equation.

p * v = m * R * T

$\frac{p}{T} = constant$

$\frac{p_{1} }{T_{1} } = \frac{p_{2} }{T_{2} }$

$p_{2} = \frac{T_{2} }{T_{1} } *p_{1}$

$p_{2} = \frac{278}{300} * 709.275$ = 657.2615 Kpa = 6.486 atm

8 0

3 years ago

A spool of thread has an average radius of 1.00 cm. If the spool contains 62.8 m of thread, how many turns of thread are on the

Simora [160]

To solve this problem we will start from the given concept in which the number of turns is equivalent to the length of the thread per circumference of spool. That is:

$N = \frac{l}{\phi}$

Where,

l = length of the thread

$\phi$ = circumference of spool

For \phi we have that,

$\phi = 2\pi r \rightarrow 2\pi (0.01)$

For l we have that

l = 62.8m

Finally the number of Turns would be,

$N = \frac{l}{\phi}$

$N = \frac{62.8}{2\pi (0.01)}$

$N = 1000turns$

Therefore the number of turns of thread on the spool are 1000turns.

7 0

3 years ago

Suppose that you are standing on a train accelerating at 0.39g. What minimum coefficient of static friction must exist between y

timurjin [86]

Answer:

0.39

Explanation:

In order not to slide, you must have exactly the same acceleration of the train:

$a=0.39 g$

where

g = 9.81 m/s^2

There is only one force acting on you: the static frictional force that "pulls" you forward, and it is given by

$F_s = \mu_s mg$

According to Newton's second law, the net force acting on you (so, the frictional force) must be equal to your mass times the acceleration, so we have

$F= ma = \mu_s mg$

from which we find

$\mu_s = \frac{a}{g}=\frac{0.39 g}{g}=0.39$

so, the minimum coefficient of static friction must be 0.39.

5 0

3 years ago