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jok3333 [9.3K]
3 years ago
7

The acceleration of positive performing SHM is 12cm/sec at distance of 3cm from the mean position its time period is?​

Physics
1 answer:
mina [271]3 years ago
4 0

Answer:

0.25 seconds

Explanation:

this is because speed is measured in metres per second

speed = distance/ time

12cm/sec = 3cm/T

T = 3cm ÷ 12cm/sec

T = 0.25sec

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How do i calculate acceleration? pls help! thanks :)
LenKa [72]

The acceleration is 2 mph/min

Explanation:

The acceleration of an object is the rate of change of velocity. It is defined as follows:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

For the car in this problem, we have (taking North as positive direction):

u = 25 mph

v = 35 mph

t = 5 min

Substituting into the equation, we find the acceleration:

a=\frac{35 mph-25mph}{5min}=2 mph/min

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

4 0
3 years ago
If the magnification produced by a lens has a negative value, the image will be
drek231 [11]

Answer:

I think it's B, not quite sure tho.

8 0
3 years ago
Read 2 more answers
Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

7 0
3 years ago
Find the magnitude of the sum<br> of these two vectors:<br><br> 101 m<br> 60.0 °<br> 85.0 m
attashe74 [19]

Answer: 161.3

I have a acellus too and got this question correct, so I hope this helps y’all out

8 0
3 years ago
A 50 Q resistor in a circuit has a current flowing through it of 2.0 A. What is
Alex17521 [72]

Hello!

We can use the following equation for calculating power dissipated by a resistor:
P = i^2R

P = Power (? W)
i = Current through resistor (2.0 A)
R = Resistance of resistor (50Ω)

Plug in the known values and solve.

P = (2.0^2)(50) = \boxed{\text{ B. }200 W}

7 0
2 years ago
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