Answer:
KE = 1/2 M V^2 = 1/2 * 25 * 10^2 = 1250 J
Check
M2 = 1/2 M1
V2 = V1 / 2
E2 = 1/2 * 1/4 E1 = E1 / 8 = 10000 / 8 = 1250 J
It sounds as though the two people are standing in front of the boat on opposite sides of it, so that they both make an angle of 30.0° with the axis of the boat, as in the attached free body diagram (ignoring the force of buoyancy and the weight of the boat).
By Newton's second law, the net vertical force is
∑ <em>F</em> = <em>P</em>₁ sin(60.0°) + <em>P</em>₂ sin(120.0°) - <em>R</em> = 0
where upward is positive and downward is negative, and the right side is 0 because the boat moves with constant velocity and thus zero acceleration.
We're told that <em>P</em>₁ = <em>P</em>₂ = 600 N, and we know sin(60°) = sin(120°), so the above reduces to
<em>R</em> = 2 <em>P</em> sin(60.0°) = 2 (600 N) sin(60.0°) ≈ 1040 N
Answer:
ωf = 8.8 rad/s
v = 2.2 m/s
Explanation:
We will use the third equation of motion to find the maximum angular velocity of the wheel:

where,
α = angular acceleration = 6 rad/s²
θ = angular displacemnt = 1 rev = 2π rad
ωf = max. final angular velocity = ?
ωi = initial angular velocity = 1.5 rad/s
Therefore,

<u>ωf = 8.8 rad/s</u>
Now, for linear velocity:
v = rω = (0.25 m)(8.8 rad/s)
<u>v = 2.2 m/s</u>
I JUST NEED POINTSSS sorry hope you do good tho!
Answer:
A. 59.4
Explanation:
The refractive index of the glass, n₁ = 1.50
The angle of incidence of the light, θ₁ = 35°
The refractive index of air, n₂ = 1.0
Snell's law states that n₁·sin(θ₁) = n₂·sin(θ₂)
Where;
θ₂ = The angle of refraction of the light, which is the angle the light will have when it passes from the glass into the air
Therefore;
θ₂ = arcsin(n₁·sin(θ₁)/n₂)
Plugging in the values of n₁, n₂ and θ₁ gives;
θ₂ = arcsin(1.50 × sin(35°)/1.0) ≈ 59.357551° ≈ 59.4°
The angle the light will have when it passes from the glass into the air, θ₂ ≈ 59.4°.