Answer:
8.33*10^-16 Watt
Explanation:
Given that
Length of the rod, l = 2 m,
Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²
resistivity of the rod, p = 6*10^-8 ohm metre,
Potential difference of the rod, V = 0.5 V
Let R be the resistance of the rod, then
R = p * l / A
R = (6*10^-8 * 2) / (4*10^-6)
R = 3*10^14 ohm
Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)
Heat = 0.25 / 3*10^14
Heat = 8.33*10^-16 Watt
Therefore, the rate at which heat is generated is 8.33*10^-16 Watt
If we consider Boyles law for gases, it states the following equation,
PV/T =k
where k is a constant
P-pressure, T- temperature and V -volume
the volume is constant at both situations as its a rigid tank as mentioned in the questions.
Therefore we consider Volume to be constant , then equation is
P/T = kV
kV = c (new constant)
P/T = c
P = cT
Therefore pressure is inversely proportional to temperature, whatever change in pressure would cause the same kind of change in temperature as well.
therefore when T decreases, P also decreases.
Answer is B
Pressure=force/area therefore pressure is inversely proportional to the area if the force is constant. As a result the pressure will be greater.
<span>The angular momentum L of a rotating wheel with mass m, radius r, moment of inertia I, angular velocity ω, and velocity v of its outer edge:
</span><span>C) Iω</span>
