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pantera1 [17]
3 years ago
7

Given a force of 56 N and an acceleration of 7 m/s2 , what is the mass?

Physics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

Your mass is 60 kg.

Explanation:

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A top fuel drag racer reaches a maximum speed of 330 mph at the end of the 1/4-mile (402 m) racetrack. Part A - Assuming that th
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Answer:

a. 27 m/s2

b. 2.75:1

Explanation:

a.

Since it is assumed that the race car starts from rest, initial velocity, u = 0 m/s

At the end of 402 m, distance, s = 402 m; and

Final velocity, v = 330 m/h

Converting this to m/s,

v=\dfrac{330\times1609}{3600}=147.5 m/s

Using the equation of motion

v^2=u^2+2as

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{147.5^2-0^2}{2\times402}=27

b.

If acceleration due to gravity is taken as 9.8 m/s2, then

a:g=27:9.8=2.75:1

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Which identifies the energy transformations that take place in Anna’s body as this process takes place?
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Chemical energy is converted to thermal energy and electrical energy.

Explanation:

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Yes you would be doing more work

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A train moving at a constant speed of 50.0 km/h moves east for 45.0 min, then in a direction 45.0° east of due north for 10.0 mi
Yuki888 [10]

Answer:

3.47km/h with a direction of 67.8 degrees north of west.

Explanation:

First we need to calculate the displacement on the X axis, so:

d_{x1}=50.0km/h*45min(\frac{1h}{60min})=37.5km\\d_{x2}=50.0km/h*10min(\frac{1h}{60min})*cos(45^o)=5.90km\\d_{x1}=-50.0km/h*55.0min(\frac{1h}{60min})=45.8km\\D_x=37.5+5.90-45.8=-2.4km

then on the Y axis:

D_y=50.0km/h*10min(\frac{1h}{60min})*sin(45^o)=5.90km

The magnitud of the displacement is given by:

D=\sqrt{D_x^2+D_y^2} \\D=6.37km

and the angle:

\alpha =arctg(\frac{5.90}{2.41})=67.8^o

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