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3 years ago

Winner of five swimming gold medals at the 1988 olympics

Physics

1 answer:

Fed [463]3 years ago

6 0

Matt Biondi..?
(I don’t know if it’s right, sorry if it is wrong)
:)

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What is a Rift Valley ?

Elenna [48]

a steep-sided valley formed by the downward displacement of a block of the earth's surface between nearly parallel faults or fault systems.

7 0

3 years ago

Read 2 more answers

Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a curre

Igoryamba

Answer:

a) $\frac{F_1}{L}=1.95*10^-^5N$

b) $\frac{F_2}{L}=1.95*10^-^5N$

Explanation:

From the question we are told that:

Distance between wires $d=32.2$

Wire 1 current $I_1=2.75$

Wire 2 current $I_2=4.33$

Generally the equation for Force on $l_1$ due to $I_2$ is mathematically given by

$F_1=I_1B_2L$

Where

B_2=Magnetic field current by $I_2$

$B_2=\frac{\mu *i_2}{2\pi d}$

Therefore

$F_1=I_1B_2L$

$F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L$

$\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }$

$\frac{F_1}{L}=1.95*10^-^5N$

Generally the equation for Force on $I_2$ due to $I_1$ is mathematically given by

$F_2=I_2B_1L$

Where

B_1=Magnetic field current by $I_2$

$B_1=\frac{\mu *I_1}{2\pi d}$

Therefore

$\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})$

$\frac{F_2}{L}=1.95*10^-^5N$

5 0

2 years ago

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

$I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})$

The dB can be calculated as:

$dB=10log(I_{n})\\$

Substitute the given values

$dB=10log(1.08*10^{11})\\dB=110.32dB$

So the sound intensity level they would experience without the earplugs is 110.32dB.

7 0

3 years ago

A proton and an electron are moving in the +x direction in a magnetic field in the +z

Cloud [144]

Answer:

Explanation:

A proton and electron are moving in the positive x direction, this shows that their velocity will be in the positive x direction

V = v•i

Magnetic field Is the positive z direction

B = B•k

A. For proton.

Proton has a positive charge of q

Direction of force on proton

Force is given as

F = q(v×B)

F = q( v•i × B•k)

F = qvB (i×k)

From vectors i×k = -j

F = -qvB •j

Then, for the positive charge, the force will act in the negative direction of the y-axis

B. For electron

Electron has a negative of -q

Direction of force on proton

Force is given as

F = q(v×B)

F = -q( v•i × B•k)

F = -qvB (i×k)

From vectors i×k = -j

F = --qvB •j

F = qvB •j

Then, for the negative charge, the force will act in the positive direction of the y-axis

5 0

3 years ago

A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's sp

Talja [164]

Using conservation of energy and momentum we get m1*v1=(m1+m2)*v2 so rearranging for v2 and plugging the given values in we get:
(200000kg*1.00m/s)/(21000kg)=.952m/s

8 0

3 years ago