Answer:
the efficiency of the Carnot engine is e=0 .5060 (50.96%)
Explanation:
The carnot cycle effifiency e is calculated through
e = W/Q₂
where
W= work
Q₂= heat absorbed
Q₁= heat exhausted
from an energy balance
W= Q₂ - Q₁ ( the proportion of the heat absorbed that was not released was converted to work)
therefore
e=(Q₂-Q₁)/Q₂ = 1 - Q₁/Q₂ = 1 - 51 J/104 J = 0.5060 (50.96%)
Answer:
C) 11 g
Explanation:
first look to graph , you have x and y
x is mass of Fe
and y is mass of product
if the reaction consumes 2 g of Fe , ( look to x axis , look to 2 )
and go up until the black line touch the line of number 2
and go left and you will see the point become in the middle between 10 and 12
** 12 (11) 10 ***
Good Luck
it is held every 4-5 years
Answer:
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Explanation:
