Answer:
Kc = 3.94
Explanation:
CH₃COOH(g) + C₂H₅OH(g) → CH₃COOC₂H₅(g) + H₂O(g)
Liquids aren't included in the equilibrium constant, but at 100°C, all four compounds are a gas. So the equilibrium equation is:
Kc = [CH₃COOC₂H₅] [H₂O] / ([CH₃COOH] [C₂H₅OH])
Set up an ICE table for each row and calculate the value of Kc. Then average the results. (See picture.)
Kc ≈ (3.919 + 4.012 + 3.902) / 3
Kc ≈ 3.94
Answer:
Acid ammonium carbonate // Ammonium bicarbonate.
Explanation:
Hello, a 4 is missing in the fist H, thus:
The presence of the hydrogen between the ammonium and the carbonates characterizes the salt as an acid salt, so you could name it as acid ammonium carbonate or ammonium bicarbonate (similar to the sodium bicarbonate which is 
.
Best regards.
PH of solution at 25ºC = 8.3
![[ H_3O^+] = 10 ^{-pH}](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%3D%2010%20%5E%7B-pH%7D%20)
![{H_3O^+] = 10 ^{-8.3}](https://tex.z-dn.net/?f=%7BH_3O%5E%2B%5D%20%3D%2010%20%5E%7B-8.3%7D)
![[H_3O^+] = 5.011*10^{-9} M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%205.011%2A10%5E%7B-9%7D%20%20M)
hope this helps!
Answer:
<h2>leaves,</h2>
Hope it helps....⋋✿ ⁰ o ⁰ ✿⋌(・o・)
