Answer:
1+6i
Step-by-step explanation:
Given:
f(x)=x^4 - 2x^3 + 38x^2 - 2 + 37
zero of f(x) = 1-6i
another zero of function = ?
Conjugate Zero theorem:
As per conjugate zero theorem, if a function f(x) has real coefficients and one of zero is a complex number then the conjugate of that complex number will also be a zero of that function i.e. complex zeroes will occur in complex conjugate pairs.
conjugate of 1-6i is 1+6i
hence another zero of f(x) will be 1+6i !
Answer:
7519 is already in the simplest form. It can be written as 3.947368 in decimal form (rounded to 6 decimal places).
Step-by-step explanation:
Answer:
5/2
Step-by-step explanation:
Y(2)-Y(1)/ X(2)-X(1)
(27-2)/(1-(-9)
25/10
simplified=5/2
(9x - 5y)(2x + 3y)
9x(2x + 3y) - 5y(2x+ 3y)
9x(2x) + 9x(3y) - 5y(2x) - 5y(3y)
18x² + 27xy - 10xy - 15y²
18x² + 17xy - 15y²