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lianna [129]
3 years ago
14

Answer from which metal these objects are made *(¡¡¡) is more important ​

Chemistry
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

(i) Electric Wires - Tin

(ii) Ornaments - Gold

(iii) Filament of bulb - Tungsten

(iv) Silvery Foil over sweets - Silver

(v) Foils to wrap food - aluminum

(vi) Pipes to supply water - Plastic or PVC pipes

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Conversación de masa 3,6kg a g​
Nikolay [14]

Explanation:

1kg = 1000g

3.6 kg = 3.6 × 100

3600g

7 0
3 years ago
2A → B + C The above reaction is run and it is found that a plot of the natural log of the concentration versus time is linear.
Alex17521 [72]

Answer:

zero order reaction

Explanation:

The seem to be a reaction is zero order as the data only fits to zero order integrated rate law.

Integrated rate law:

[A] = [A]_0 – kt

Here y = [ A] and slope is -k , so when we plot concentration of A with respect to t then we get the equation in the form of line

y = mx + c

So the answer Zero order in [A]

3 0
4 years ago
What is a physical change
kompoz [17]
It's changing a thing with force, not chemicals, like cutting paper
8 0
4 years ago
Iron has a density of 7.86 g/cm^3 (1 cm^3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4.62 kg . Note
s2008m [1.1K]

Density is mass over volume. The density of iron is given in g/cm³

we have to first convert g/cm³ to kg/dL.

1000 g = 1 kg and 100 cm³ = 1 dL

the mass of 1 cm³ = 1 g

the mass of 100 cm³ / 1 dL = 100 g

then mass of 1 dL in kg is = 100 g / 1000 g/kg = 0.1 kg

volume of 0.1 kg is 1 dL

therefore density of iron is 7.86 g/cm³ x 0.1 kg/dL / g/cm³ = 0.786 kg/dL

volume of iron having mass 0.786 kg is 1 dL

then volume of iron having a mass of 4.62 kg is - 1 dL / 0.786 kg x 4.62 kg = dL

volume of iron is 5.88 dL

3 0
3 years ago
What is T2, if T1= 500 k, v1=10L, V2=8L,P1=600 torr,P2=200 torr?
Molodets [167]

Answer:

T2 = 133.333°K

Explanation:

Using Combined Gas Laws:

(600 torr)(10L)/500°K = (200 torr)(8L)/x°K

\frac{600 torr(10L)}{500K} =\frac{200 torr(8L)}{xK}

Cross multiply:

x°K (600 torr)(10L) = 500°K(200 torr)(8L)

Divide:

x°K = (500°K(200 torr)(8L))/(600 torr)(10L)

xK = \frac{500K(200 torr)(8L)}{600 torr(10L)}

x = 400/3°K or 133.333°K

8 0
3 years ago
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