Answer:
newtons law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of the distance between their centers
Answer: two moles
Explanation:
In one mole of fe2o3 there are two moles of iron atoms. Now gram atomic wt. of Fe is 56.So in one mole of Fe2O3 there are 2×56=112 gm of Fe. Hence in 1.75molesFe2O3 there are 1.75×2 moles or 1.75×56 gm of iron
Answer:
<span>In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is <u>Hydrogen atom of HBr</u>.
Explanation:
In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.</span>
Based on this, Individual electrons in graphene have almost no mass compared to the other particles.
The material graphene consists of a single layer of carbon atoms arranged in a hexagonal lattice.
Electrons flowing through graphene can be scattered from impurities (such as foreign atoms in the lattice), from other electrons and from lattice vibrations known as phonons.
What happens to the electrons in graphene?
According to the researchers, such high values are a result of the photo thermoelectric effect. “It turns out that when you shine a light on graphene, the electrons in the material heat up, and remain hot, while the underlying carbon lattice remains cool,”
Why are electrons massless in graphene?
Yes, low energy electrons and holes in graphene can be thought of as massless because of the linear dispersion of the band structure near the K points.
This is an analogy to the relativistic energy dispersion E2=P2C2+M2C4, which becomes linear in momentum for m=0.
To learn more about electrons here
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The answer to the question is the first opti.on.A
