37.8 grams of CS2 equals to 37.8/76=0.5 mole. So the products have 0.5 mole CO2 which is 11.2 liters at STP. So according to the gas law, the volume at given condition is 12.4 liters. So the answer should be 12.2 liters.
Answer is: 25,06 kJ of energy must be added to a 75 g block of ice.
ΔHfusion(H₂O) = 6,01 kJ/mol.
T(H₂O) = 0°C.
m(H₂O) = 75 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 75 g ÷ 18 g/mol.
n(H₂O) = 4,17 mol.
Q = ΔHfusion(H₂O) · n(H₂O)
Q = 6,01 kJ/mol · 4,17 mol
Q = 25,06 kJ.
Answer:
[C] = 0.4248M
Explanation:
A + B ⇄ 2C
C(i) 1.68M 1.68M 0.00
ΔC -x -x +2x
C(eq) 1.68-x 1.68-x 2x
Keq = [C]²/[A][B] = (2x)²/(1.68 - x)²= 8.98 x 10⁻²
Take SqrRt of both sides => √(2x)²/(1.68 - x)² = √8.98 x 10⁻²
=> 2x/1.68 - x = 0.2895
=> 2x = 0.2895(1.68 - x)
=> 2x = 0.4863 - 0.2895x
=> 2x + 0.2895x = 0.4863
=> 2.2895x = 0.4863
=> x = 0.4863/2.2895 = 0.2124
[C] = 2x = 2(0.2124)M = 0.4248M in 'C'
Answer:
a. Calcium
Explanation:
Strontium and Calcium are both in the same group, Group 2.
