A rectangular field has the area equal to that of a square field of side 60m.if the breadth of the rectangular field is 32m, fin
1 answer:
<u>Given</u> -
- Area of rectangular field = Area of square field
- side of square = 60m
- breadth of the rectangular field = 32m
<u>To find</u> -
- length of the rectangular field
<u>Solution</u> -
Area of square = side × side = (60 × 60)m² =
Area of square =3600m²
Hence,
Area of rectangular field = Area of square field = 3600m²
Area of rectangular field = l × b = 3600m²
=> l × 32m = 3600m²
=> l =
=> l = 112.5m
so, the length = 112.5m
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Answer:
Option A
Step-by-step explanation:
This is a great question!
The first thing we want to do here is to graph the system of " inequalities " -
As x is ≥ 0, respectively y ≥ 0, it makes things a lot simpler, as it kind of restricts us to quadrant 1, but not entirely.
First change each inequality to " slope - intercept " form, as such -
The graphed solutions would be in the attachment. I have colored the region with which the two intersect, and the fact that we are limited to quadrant 1. In this colored region there are 3 major points, ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ). We have to determine which of these are are maximum points, as the minimum are the same. Substitute these values ( ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ) ) into the equation f( x, y ) = 10x + 4y,
( 5, 9 ) resulted in the greatest amount, 86. That would make it our maximum point -
<u><em>Solution = Option A</em></u>
