Answer:
a. v = 7.5 m/s
b. w = 50 rad/s
c. 46.667 rad
Explanation:
Using the equations of energy in the motion to determine the speed, angular speed and the angle
Ep = m * g * h
, ⇒ h = 7m * sin 35
Ep = 1.5kg * 9.8m/s^2 * 7 m * sin 35
Ep= 59.02 J
Ek = ½ * m * v^2 , ⇒Ek = ½ *1.5 kg* v^2
Ew = ½ * I * ω^2 For a solid sphere I = 2/5 * m * r^2 ⇒ I = 2/5 * 1.5 * 0.15^2 = 0.0135
ω = v/0.15, ω^2 = v^2/0.0225
Ek = ½ * 0.0135 * v^2/0.0225
Ek = 0.3 * v^2
Total E = 0.75 * v^2 + 0.3 * v^2
E = 1.05 * v^2
59.02 J = 1.05 * v^2
v = √56.2 = 7.5 m/s
ω = 7.5 / 0.15 = 50 rad/s
C= 2 * π * 0.15 = 0.3 * π
θ =[ 7 /(0.3 * π) ] * (2 π)
θ= 46.667 rad
Answer:
Output voltage is 1.507 mV
Solution:
As per the question:
Nominal resistance, R =
Fixed resistance, R =
Gauge Factor, G.F = 2.01
Supply Voltage,
Strain,
Now,
To calculate the output voltage, :
WE know that strain is given by:
Thus
Now, substituting the suitable values in the above eqn:
Answer:
The slowdown took 2.05 seconds and the roller coaster made a distance 20.5 during that time.
Explanation:
Start with the kinematic equation for velocity. Let v1 and v2 be the initial and the new velocity, respectively. Let s denote the distance made duringthe slowdown. Let m denote the mass of the roller coaster and "a" its acceleration (negative = deceleration). the equation is as follows:
Let us first determine the distance made:
The roller coaster made 20.5 meters during slowing down to 2 m/s. Now calculate the time this took.
It took 2.05 seconds to achieve the slowdown from 18 to 2 m/s
Answer:
39.8 °C
Explanation:
m = mass of the ice = 100 g
L = latent heat of fusion of ice = 334 Jg⁻¹
M = mass of water = 200 g
= specific heat of water = 4.2 Jg⁻¹°C⁻¹
= initial temperature of water = ?
= final temperature of water = 0 °C
Using conservation of heat
Heat gained by ice = heat lost by water
m L = M ( - )
(100) (334) = (200) (4.2) ( - 0 )
= 39.8 °C
Gravitational pull
Hope I helped