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IceJOKER [234]
3 years ago
13

A.Substitute in the units for each one and combine like terms.

Physics
1 answer:
storchak [24]3 years ago
8 0
IDK     ghjfnhgfjmrmhjgfhgfmmfh
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Which of the following is proportional to the net external force acting on a body?
swat32
Well, Velocity is the speed of something in a given direction, and speed is the rate at which someone or something is able to more or operate. They both invlove speed, so this is a hard one, but I wold say either B or D
5 0
2 years ago
Using the strap at an angle of 31.0° above the horizontal, a Grade 12 Physics student, tired from studying, is dragging his 15.0
lora16 [44]

Answer:

<h2>154.73N</h2>

Explanation:

The question is incomplete. Here is the complete question.

Using the strap at an angle of 31° above the horizontal, a Grade 12 Physics student, tired from studying, is dragging his 15 kg school bag across the floor at a constant velocity. (a) If the force of tension in the strap is 51 N, what is the normal force.

Check the diagram related to the question in the attachment below for better understanding.

The normal force is the reaction acting perpendicular to the force of tension in the strap and opposite the weight of the bag. They are the forces acting along the vertical.

The normal force N will be the sum of the force of tension acting along the vertical (Ty) and the weight of the bag (W).

Ty = 15sin31°

Ty = 7.73N

W = mass * acceleration due to gravity

W = 15.0*9.8

W = 147N

The normal force is therefore expressed as;

N = Ty + W

N = 7.73 + 147

N = 154.73N

3 0
3 years ago
4: A piece of fur is negatively charged when:
MatroZZZ [7]

Answer:

the fur is unexpected

Explanation:

idk

5 0
3 years ago
Neither _____ nor _____ can be created or destroyed, but they can be changed from one to the other
Viktor [21]

Matter nor energy

hope this helps

3 0
3 years ago
Read 2 more answers
In an elastic collision, a 580 kg bumper car collides directly from behind with a second, identical bumper car that is traveling
kozerog [31]

Answer:  vl = 2.75 m/s vt = 1.5 m/s

Explanation:

If we assume that no external forces act during the collision, total momentum must be conserved.

If both cars are identical and also the drivers have the same mass, we can write the following:

m (vi1 + vi2) = m (vf1 + vf2) (1)

The sum of the initial speeds must be equal to the sum of the final ones.

If we are told that kinetic energy must be conserved also, simplifying, we can write:

vi1² + vi2² = vf1² + vf2² (2)

The only condition that satisfies  (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:

vf1 = vi2 and vf2 = vi1

If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:

vf1 = 2.75 m/s  vf2 = 1.5 m/s

8 0
3 years ago
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