Answer:
Part a)
V = 18.16 V
Part b)

Part c)
P = 672 Watt
Part d)
V = 5.84 V
Part e)

Explanation:
Part a)
When battery is in charging mode
then the potential difference at the terminal of the cell is more than its EMF and it is given as

here we have



now we have

Part b)
Rate of energy dissipation inside the battery is the energy across internal resistance
so it is given as



Part c)
Rate of energy conversion into EMF is given as



Now battery is giving current to other circuit so now it is discharging
now we have
Part d)



Part e)
now the rate of energy dissipation is given as



Answer:
A ball is thrown straight up with a speed of 30
m/s. What is the maximum height reached by
the ball?
<span>An imaginary line perpendicular to a reflecting surface is called "a normal" (principle line)
So, Your Answer would be Option B
Hope this helps!</span>
Answer: The distance is 723.4km
Explanation:
The velocity of the transverse waves is 8.9km/s
The velocity of the longitudinal wave is 5.1 km/s
The transverse one reaches 68 seconds before the longitudinal.
if the distance is X, we know that:
X/(9.8km/s) = T1
X/(5.1km/s) = T2
T2 = T1 + 68s
Where T1 and T2 are the time that each wave needs to reach the sesmograph.
We replace the third equation into the second and get:
X/(9.8km/s) = T1
X/(5.1km/s) = T1 + 68s
Now, we can replace T1 from the first equation into the second one:
X/(5.1km/s) = X/(9.8km/s) + 68s
Now we can solve it for X and find the distance.
X/(5.1km/s) - X/(9.8km/s) = 68s
X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s
X = 68s/0.094s/km = 723.4 km