Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;

Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Answer:
I don't know the answer I need points before I fail my math test
Answer: When fire stopping material is used where more than 2 non-metallic sheathed cables pass through wood framing members, their ampacities must be adjusted, according to 310.15"
Answer is 2
Answer:
The RMS voltage across the resistor = 28 V
Explanation:
Capacitor: A capacitor is an electrical device that has the ability to store electrical charges in an electrical circuit. It is expressed in Farad (F)
Resistor: A resistor is an electrical device that oppose the flow of electric current in a circuit. It is expressed in ohms (Ω)
RMS Voltage : RMS voltage value of an alternating voltage is defined as that value of steady voltage which would dissipate heat at the same rate in a given resistance
Since the it is a series circuit, the total voltage is divided across the resistance and the capacitor.
Vt = V₁ + V₂...........................Equation 1
Where Vt = total Rms voltage = 120 V , V₁ = Rms voltage across the Capacitor = 92 V, V₂ = Rms voltage across the resistor.
Making V₂ the subject of the equation in equation 1 above,
V₂ = Vt - V₁ = 120 - 92
V₂ = 28 V.
The RMS voltage across the resistor = 28 V
To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,
Frequency 
Speed of sound in air 
The definition of wavelength is,

Here,
v = Velocity
f = Frequency
Replacing,


Therefore the wavelength of that tone in air at standard conditions is 0.589m