Answer:
K= 95.4 J
Explanation:
For this exercise we must use the conservation of mechanical energy.
We set a reference system on the floor.
Starting point. Higher
Em₀ = U = m g h
Final point. Just before taking the floor
Em_f = K = ½ m v²
energy is conserved because there is no friction
Em₀ = Em_f
mg h = K
The height is
- h = y -y₀
h = 0- y₀
let's calculate
K = 3.23 (-9.81) (-3.01)
K= 95.4 J
C it reduces the amount of useful work done on objects move it up the ramp
Answer:
In a cardio kickboxing class, you will learn proper form for the famous jab, hooks,crosses, uppercuts, back kicks, front kicks.
Explanation:
