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lesantik [10]
3 years ago
12

A child rides a carousel with a radius of5.1 that rotates with a constant speed of2.2 m/s. Calculate the magnitude of the centri

petal acceleration of the child.​
Physics
1 answer:
kramer3 years ago
8 0

Answer:

hey i’m gonna do guess that song if y’all wanna follow me or something or guess the song lol

Explanation:

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Rate in miles/hours if your run at a speed 2.2 20miles
Vinvika [58]
9.1 miles per hour because 2.2 is your hours right?
5 0
4 years ago
Calculate the total resistance in a parallel circuit made up of resistances of 2, 3, and 4.
Tamiku [17]

Answer:

<em><u>0</u></em><em><u>.</u></em><em><u>9</u></em><em><u>1</u></em>

Explanation:

as equivalence resistance can be found out using the

1/Req = 1/r1 +1/r2 +1/r3......

now, 1/req= 1/2+1/3+1/4

=6/12+4/12+3/12

=13/12

i.e, req =12/13 =0.91

✌️:)

5 0
4 years ago
Charges of +5C and −9C are at a distance of 1m from each other. Which diagram represents the force between the two charges?
weqwewe [10]

the answer is CCCCCCCCCCCCCCCCC

8 0
4 years ago
Read 2 more answers
Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is
Oksi-84 [34.3K]

Answer:

Explanation:

Heat capacity A = 3 x heat capacity of B

initial temperature of A = 2 x initial temperature of B

TA = 2 TB

Let T be the final temperature of the system

Heat lost by A is equal to the heat gained by B

mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)

heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)

3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB)

3 TA - 3 T = T - TB

6 TB + TB = 4 T

T = 1.75 TB

8 0
4 years ago
A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces
Flura [38]

Answer: (b)

Explanation:

Given

Mass of box m=17\ kg

Applied force F=175\ N

Friction force f=-125\ N

Box travels a distance of s=15\ m

time taken t=5.25\ s

Net unbalanced force F_{net}=175-125=50\ N

Work done by the unbalanced force

\Rightarrow W=F_{un}\cdot s\\\Rightarrow W=50\times 15\\\Rightarrow W=750\ N

Power developed by unbalanced force

\Rightarrow P=\dfrac{W}{t}\\\\\Rightarrow P=\dfrac{750}{5.25}\\\\\Rightarrow P=142.85\approx 1423\ W

Thus, option (b) is correct.

7 0
3 years ago
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