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siniylev [52]
3 years ago
10

A skateboarder flies horizontally off a cement planter. After 3 seconds the skateboarder lands on the ground with a final veloci

ty of −4.5 m/s. Which kinematic equation would be most useful for finding the skateboarder’s initial velocity? (Assume a=−9.8 ms^2)
B
C or E
A
D

Physics
1 answer:
evablogger [386]3 years ago
3 0

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

v = v_o + a \Delta t

A skateboarder flies horizontally off a cement planter. After a time of 3 seconds (Δt), he lands with a final velocity (v) of −4.5 m/s. Assuming the acceleration is -9.8 m/s² (a), we can calculate the initial velocity of the skateboarder (v₀) using the kinematic equation A.

v = v_o + a \Delta t\\\\v_o = v - a \Delta t = (-4.5 m/s) - (-9.8 m/s^{2} ) \times 3 s = 24.9 m/s

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

v = v_o + a \Delta t

Learn more: brainly.com/question/4434106

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The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
Inessa05 [86]

Answer:

a) 4.40 s

b) 2.20 s

Explanation:

Given parameters are:

At constant power  ,

initial speed of the car, v_0=0

final speed of the car, v=32 mph

At full power,

initial speed of the car, v_0=0

final speed of the car, v=64 mph

a)

At constant power, KE = \frac{1}{2} mv^2

At full power, KE = \frac{1}{2} m(2v)^2

So KE_f = 4KE_i

So, time to reach 64 mph speed is 4 times more than the initial time

t = 4*1.10 =4.40 s

b)

v=v_0+at\\a=\frac{v-v_0}{t}=\frac{32-0}{1.1/3600}=104727.27 miles/hours^2

For final 64 mph speed,

v=v_0+at\\t=\frac{v-v_0}{a}=\frac{64-0}{104727.27} = 6.111*10^{-4} hours = 6.111*10^{-4}*3600=2.20 s

7 0
2 years ago
What characteristic distinguishes a group from an aggregate?
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Group is a collection of people that are in the same place and share some characteristics. examples are a group of students, a group of engineers and etc. while aggregate is a collection of people that are in the same place but do not share anything in common
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What life process requires specialized cells in multicellular organisms
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The wave frequency is where 1 hertz equals 1 wave passed a fixed point in 1 second.
ahrayia [7]

                     (10 waves) / (5 sec) 

                 =  (10/5) (wave/sec)

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3 0
2 years ago
A person's center of mass is very near the hips, at the top of the legs. Model a person as a particle of mass mm at the top of a
muminat

Answer:

\mathbf{v_{max} = \sqrt{gL}}

Explanation:

Considering an object that moving about in a circular path,  the equation for such centripetal force can be computed as:

\mathbf {F = \dfrac{mv^2}{2}}

The model for the person can be seen in the diagram attached below.

So, along the horizontal axis, the net force that is exerted on the person is:

mg cos \theta = \dfrac{mv^2}{L}

Dividing both sides by "m"; we have :

g cos \theta = \dfrac{v^2}{L}

Making "v" the subject of the formula: we have:

v^2 = g Lcos \theta

v=\sqrt{ gL cos \theta

So, when \theta = 0; the velocity is maximum

∴

v_{max} = \sqrt{gL \ cos \theta}

v_{max} = \sqrt{gL \ cos (0)}

v_{max} = \sqrt{gL \times 1}

\mathbf{v_{max} = \sqrt{gL}}

Hence; the maximum walking speed for the person  is \mathbf{v_{max} = \sqrt{gL}}

3 0
3 years ago
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