The speed of the sport car at the time of impact is 6.61 m/s.
<h3>What is the frictional force of the two cars?</h3>
Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity
= 0.8 × (2500+940) × 9.8
= 26970N
<h3>What is the acceleration of the skidded cars?</h3>
- As per Newton's second law of motion, force = mass × acceleration
- Acceleration= force / mass
= 26,970/3440
= 7.8 m/s²
<h3>What is the velocity of the sport car at the time of impact?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- Here, V = 0 m/s, a= -7.8 m/s², S= 2.8 m
- So, 0²-U²= 2×(-7.8)×2.8
=> U = √43.68
= 6.61 m/s
Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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Answer:
Galactic Zone Grounds
Located in the employees only area by some dumpsters and a body. Located at the top of the Arcjet Tower. After exiting Nuka-Galaxy, check behind the gate for a star core. After you've turned the power on in Power Play, take the elevator in Starport Nuka to the top floor to find a star core.
This is an example of state change from solid to liquid.
Answer:
(a) 112.5 V/m
(b) 0.01494 T
Explanation:
velocity, v = 4.5 km/s = 4500 m/s
magnetic field, B = 2.5 x 10^-2 T
mass, m = 6.64 x 10^-26 kg
charge, q = 1.6 x 10^-19 C = 1.6 x 10^-19 C
(a) The force due to the magnetic field is balanced by the force due to the electric field
q E = B q v
E = B v = 2.5 x 10^-2 x 4500 = 112.5 V/m
(b) radius, r = 12.5 cm
B' = 0.01494 T
Back emf is 85.9 V.
<u>Explanation:</u>
Given-
Resistance, R = 3.75Ω
Current, I = 9.1 A
Supply Voltage, V = 120 V
Back emf = ?
Assumption - There is no effects of inductance.
A motor will have a back emf that opposes the supply voltage, as the motor speeds up the back emf increases and has the effect that the difference between the supply voltage and the back emf is what causes the current to flow through the armature resistance.
So if 9.1 A flows through the resistance of 3.75Ω then by Ohms law,
The voltage across the resistance would be
v = I x R
= 9.1 x 3.75
= 34.125 volts
We know,
supply voltage = back emf + voltage across the resistance
By plugging in the values,
120 V = back emf + 34.125 V
Back emf = 120 - 34.125
= 85.9 Volts
Therefore, back emf is 85.9 V.