How does the valence bond theory describe a covalent bond formation?

For the homogeneous solution, consisting of kcl and h2o, indicate the type of forces that are involved.

zubka84 [21]

<span>The pairs of substances I would expect to form homogeneous solutions when combined will form a homogeneous because both are polar and form dispersion forces, dipole-dipole and hydrogen bonding between the water molecules and ion-dipole forces between the K+ and Cl- ions and the water molecules.</span>

4 0

3 years ago

A rectangle has a length of 5.50m and a width of 12.0m. What is the area of this rectangle?

jolli1 [7]

Answer:

66m

Explanation:

To get the area of something you multiple the length (5.5) by the width (12) together. So the problem would look like 5.5×12 and if you multipe that you get 66

3 0

2 years ago

Which of the following observations about pH is consistent for an acidic solution?

kow [346]

Answer:

A pH value of 3

Explanation:

The pH scale has 14 numbers:

- 7 is a true natural

-anything above 7 is a base

-and anything under 7 is an acid

pH of three is a strong acid

5 0

8 months ago

Basilosaurus cetoides was a large mammal that existed 35 million years ago. It was 20 m long and had a large skull, incompletely

Korvikt [17]

Answer: hey so I’m taking the same test as you right now. I’m on that question and I searched it up and came on here. Would you mind telling me the answer?

Explanation:

5 0

2 years ago

At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

Alekssandra [29.7K]

Explanation:

$Density =\frac{Mass}[Volume}$

Density of the air ,d= 1.189 g/L

(a) Density of the evacuated ball

Mass of the ball ,m = 0.12 g

Volume of the ball = $V=560 cm^3=560 ml=0.560 L$

$D =\frac{0.12 g}{0.560 L}=0.214 g/L$

D<d, teh evacuated ball will flaot in air.

(b) Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = $d_1=1.830 g/L$

Mass of the carbon dioxide gas :

$1.830 g/L\times 0.560 L=1.0248 g$

Total density of filled ball with carbon dioxide gas:

$\frac{0.12 g+1.0248 g}{0.560 L}==2.044 g/L$

The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air.

(c) Density of the evacuated ball D = 0.214 g/L

Density of hydrogen gas = $d_2=0.0899 g/L$

Mass of the hydrogen gas :

$1.830 g/L\times 0.560 L=0.050344 g$

Total density of filled ball with hydrogen gas:

$\frac{0.12 g+0.050344 g}{0.560 L}==0.3041 g/L$

The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

(d) Density of the evacuated ball D = 0.214 g/L

Density of oxygen gas = $d_3=1.330 g/L$

Mass of the oxygen gas :

$1.330 g/L\times 0.560 L=1.7448 g$

Total density of filled ball with oxygen gas:

$\frac{0.12 g+1.7448 g}{0.560 L}=1.5442 g/L$

The ball filled with oxygen will not float in the air because total density of filled ball is greater than the density of an air.

(e) Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = $d_4=1.165 g/L$

Mass of the nitrogen gas :

$1.165 g/L\times 0.560 L=0.6524 g$

Total density of filled ball with nitrogen gas:

$\frac{0.12 g+0.6524 g}{0.560 L}==1.3792 g/L$

The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air.

f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

$\frac{0.12g +m}{0.560L}>1.189 g/L$

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

5 0

2 years ago