229.25 mL of isopropyl alcohol
425.75 mL of water
Explanation:
Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.
volume of isopropyl alcohol = (35/100) × solution volume
volume of isopropyl alcohol = 0.35 × 655 mL = 229.25 mL
Now, knowing the volume of isopropyl alcohol we can determine the volume of water.
volume of the solution = volume of isopropyl alcohol + volume of water
volume of water = volume of the solution - volume of isopropyl alcohol
volume of water = 655 mL - 229.25 mL = 425.75 mL
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percent by volume concentration
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Answer:
The experimenter observed this experiment in a lab rather than natural world because it might be dangerous to the atmosphere if he does the experiment in the natural world and it was still an hypothesis so that's why he did it in the lab.
From the calculation, the standard free energy of the system is -359kJ.
<h3>What is the standard free-energy?</h3>
The standard free-energy is the energy present in the system. We have to first obtain the cell potential using the formula;
Ereduction - E oxidation = 0.96 V - 0.34 V = 0.62 V
Using the formula;
ΔG = -nFEcell
ΔG =-(6 * 96500 * 0.62)
ΔG =-359kJ
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Answer:
0.8 mL of protein solution, 9.2 mL of water
Explanation:
The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:
C₁V₁ = C₂V₂
We would like to calculate the value for V₁, the volume of the inital solution that we need to dilute to make the required solution.
V₁ = (C₂V₂) / C₁ = (2mg/mL x 10mL) / (25 mg/mL) = 0.8 mL
Thus, a volume of 0.8 mL of protein solution should be diluted with enough water to bring the total volume to 10 mL. The amount of water needed is:
(10 mL - 0.8 mL) = 9.2 mL
Answer:
Nucleus
Explanation: it is the center of the atom, and contains protons and nuetrons
