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weeeeeb [17]
3 years ago
8

At a given temperature, Kc=1.3x10-2 for reaction 1. What is the value of Kc for reaction 2? Reaction 1: begin mathsize 12px styl

e N subscript 2 open parentheses g close parentheses plus 3 H subscript 2 open parentheses g close parentheses rightwards harpoon over leftwards harpoon 2 N H subscript 3 open parentheses g close parentheses end style Reaction 2: begin mathsize 12px style 4 N H subscript 3 open parentheses g close parentheses rightwards harpoon over leftwards harpoon space 2 N subscript 2 open parentheses g close parentheses plus 6 H subscript 2 open parentheses g close parentheses end style

Chemistry
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

See explaination

Explanation:

For a reversible reaction, the equilibrium constant for a backward reaction is reciprocal.

If the coefficients in a balanced equation are multiplied by a factor, n, the equilibrium expression is raised to the nth power.

K' = (K)^n

In the second reaction the value kf n is 2. The first reaction is multiplied by 2.

See attachment for further solution

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