At a given temperature, Kc=1.3x10-2 for reaction 1. What is the value of Kc for reaction 2? Reaction 1: begin mathsize 12px styl
e N subscript 2 open parentheses g close parentheses plus 3 H subscript 2 open parentheses g close parentheses rightwards harpoon over leftwards harpoon 2 N H subscript 3 open parentheses g close parentheses end style Reaction 2: begin mathsize 12px style 4 N H subscript 3 open parentheses g close parentheses rightwards harpoon over leftwards harpoon space 2 N subscript 2 open parentheses g close parentheses plus 6 H subscript 2 open parentheses g close parentheses end style
1 answer:
Answer:
See explaination
Explanation:
For a reversible reaction, the equilibrium constant for a backward reaction is reciprocal.
If the coefficients in a balanced equation are multiplied by a factor, n, the equilibrium expression is raised to the nth power.
K' = (K)^n
In the second reaction the value kf n is 2. The first reaction is multiplied by 2.
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Answer:
Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17
Explanation:
Energy released during the complete combustion of 1 mole glucose = 2870 kJ
Energy required/muscle contraction cycle = 67 kJ/contraction
Energy conversion efficiency = 39%
Actual amount of energy converted to contraction per mole of glucose is:
Total contraction cycles fueled by the above energy is: