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Tcecarenko [31]
3 years ago
8

Question 2

Chemistry
2 answers:
SIZIF [17.4K]3 years ago
4 0
NaCl

This is metal (Na) and nonmetal (Cl)

This makes it ionic!!!
QveST [7]3 years ago
3 0
Metals only and ionic
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Ethane, C2H6, can be formed by reacting acetylene, C2H2, with hydrogen gas as follows: C2H2(g) H2(g) ⇌ C2H6(g) Exothermic What c
Pavel [41]

Answer:

Equilibrium shifts to the right

Explanation:

An exothermic reaction is one in which temperature is released to the environment. Hence, if the reaction vessel housing an exothermic reaction is touched after reaction completion, we will notice that the reaction vessel e.g beaker is hot.

To consider the equilibrium response to temperature changes, we need to consider if the reaction is exothermic or endothermic. In the case of this particular question, it has been established that the reaction is exothermic.

Heat is released to the surroundings as the reactants are at a higher energy level compared to the products. Hence, increasing the temperature will favor the formation of more reactants and as such, the equilibrium position will shift to the left to pave way for the formation of more reactants. Thus , more acetylene and hydrogen would be yielded

8 0
3 years ago
What adaptations allow a camel and a cactus to survive in warm environments?
lesya [120]

Answer:

A camel stores fat in its hump, while the cactus stores water in its thick stem.

Explanation:

8 0
3 years ago
Read 2 more answers
Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell
olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0
3 years ago
How many different compounds are possible, changing only the cis/trans arrangements around these two double bonds?
insens350 [35]
Check the attached file for the answer.

3 0
3 years ago
Zn-64 = 48.63%
sladkih [1.3K]

Answer:

A = 65.46 u

Explanation:

Given that,

The composition of zinc is as follows :

Zn-64 = 48.63%

Zn-66 = 27.90%

Zn-67 = 4.10%

Zn-68 = 18.75%

Zn-70 = .62%

We need to find the  average atomic mass of the given element. It can be solved as follows :

A=\dfrac{48.63\times 64+27.90\times 66+4.1\times 67+18.75\times 68+0.62\times 70}{100}\\A=65.46\ u

So, the average atomic mass of zinc is 65.46 u.

6 0
2 years ago
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