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Lelechka [254]
3 years ago
9

Twenty-seven pounds (27 lb) of chlorine gas is used for treating 750,000 gal of water each day. The chlorine used up by the micr

oorganisms in the water is measured to be 2.6 mg/L. What is the residual (excess) chlorine concentration in the treated water?
Chemistry
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

The correct answer is 1.778 milligrams per liter.

Explanation:

Based on the given information, the concentration of chlorine gas given is 27 pounds or 27*453.59 = 12327.93 grams.

The quantity of water given is 750000 gallons or 750000 * 3.754 = 2815500 L

The concentration of chlorine used up by the microorganism is 2.6 mg/L or 0.0026 gm/L.

Thus, for 2815500 L of water, the amount of chlorine used is,

= 2815500 * 0.0026

= 7320.3 grams

The left quantity of chlorine is 12327.93 - 7320.3 = 5007.63 grams

The concentration of residual chlorine is,

= 5007.63 g/2815500 = 0.00177859 or 1.778 mg/L.

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7 0
3 years ago
How many grams are in 1.946 moles of nacl
Ilia_Sergeevich [38]

Answer:

113.8g

Explanation:

Statement of problem: mass of 1.946mole of NaCl

Given parameters:

Number of moles of NaCl = 1.946mole

Unknown: mass of NaCl

Solution

To find the mass of NaCl, we apply the concept of moles which expresses the relationship between number of moles and mass according to the equation below:

                        Number of moles = \frac{mass}{molar mass}

To find the molar mass of NaCl:

                         the atomic mass of Na = 23g

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                Molar mass of NaCl = (23 + 35.5) = 58.5gmol⁻¹

Mass of NaCl = Number of moles x molar mass of NaCl

Mass of NaCl = 1.946 x 58.5 = 113.8g

7 0
3 years ago
I need the answer to 452 of arogon
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Is this an example of decomposition<br> 2CH4 + 402 → 2C02 + 4H2O
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Answer:

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In this equation, two substances combine to make a single substance. This is a composition reaction.

Two different substances react to make two new substances. This does not fit the definition of either a composition reaction or a decomposition reaction, so it is neither. In fact, you may recognize this as a double-replacement reaction.

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Digiron [165]

Answer:

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