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lawyer [7]
3 years ago
11

If the electron affinity for an element is negative, this means that

Chemistry
1 answer:
AlladinOne [14]3 years ago
8 0

Answer: If the electron affinity is negative, it indicates the release of energy from the atom. Hope this helps :)

Explanation:

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The proper way to chemically write carbon dioxide is CO2
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HELP!! Suppose that the pressure of 1.00 L of gas is 380 mm Hg when the temperature is 200. K. At what
Korolek [52]
Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.



sendo:

τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)


temos: τ = Q1 - Q2

O rendimento (η) é a razão do trabalho realizado pela energia fornecida:

η= τ/Q1

Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.

solução:

τ=3500 J
Q1=5000J

η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%

Energia dissipada será:



τ = Q1 - Q2
Q2 = Q1- τ

Q2=5000-3500
Q2= 1500 J

Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?



obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem
4 0
3 years ago
SbF5 mass ratio and atomic ratio
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Answer:

SbF5

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7 0
3 years ago
What are the final hydrogen ion concentration and pH of a solution obtained by mixing 400mL of 0.2M NaOH with 150mL of 0.1M H3PO
dusya [7]

Explanation:

The chemical reaction equation will be as follows.

      H_{3}PO_{4} + 3NaOH \rightarrow Na_{3}PO_{4} + 3H_{2}O

In this reaction, 1 mole of H_{3}PO_{4} reacts with 3 mole NaOH. So, the number of moles of H_{3}PO_{4} present  in 150 ml of 0.1 M solution is calculated as follows.

               No. of moles = \frac{150}{1000 \times 0.1}  

                                      = 0.015 mol

As it reacts with 3 moles of NaOH. Hence, no.. of moles of NaOH are:

                           3 \times 0.015 mol

                              = 0.045 mol

So, moles of NaOH in 400 of 0.2 M NaH is as follows.

                No. of moles = \frac{400}{1000 \times 2}

                                       = 0.080 mol

Hence, no. of moles remained after the reaction are as follows.

                 (0.080 - 0.045) mol

               = 0.035 mol NaOH in 550 ml (400 ml + 150 ml)

As molarity is the no. of moles present in liter of solution. Hence, molarity of   NaOH is as follows.

     Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                    = \frac{0.035}{550}        

                   = 0.0636 M

As, [OH^{-}] = 0.0636 M. Hence, pOH will be 1.20.

As,           pH + pOH = 14

                  pH = 14 - pOH

                        = 14 - 1.20

                        = 12.80

Also, [H^{+}] = 10^{-pH}    

So,          [H^{+}] = 10^{-12.80}    

                           = 1.58 \times 10^{-13} M

Thus, we can conclude that pH of the given solution is 12.80 and its hydrogen ion concentration is 1.58 \times 10^{-13} M.

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