Answer:
0.162 moles of CO₂ are produced by this reaction
Explanation:
The reaction is:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) +4H₂O(g)
As we have the volume of propane, we need to know the mass that has reacted, so we apply density's concept.
Density = Mass / Volume → Density . Volume = Mass
0.00183 g/mL . 1300 mL = Mass → 2.379 g
We determine the moles → 2.379 g . 1mol / 44 g = 0.054 moles
Ratio is 1:3. 1 mol of propane can produce 3 moles of dioxide
Then, 0.054 moles may produce (0.054 .3)/1 = 0.162 moles
464 g radioisotope was present when the sample was put in storage
<h3>Further explanation</h3>
Given
Sample waste of Co-60 = 14.5 g
26.5 years in storage
Required
Initial sample
Solution
General formulas used in decay:
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of Co-60 = 5.3 years
Input the value :
Answer:
duplet-A set of two things or people
Octet-A group of 8 things or people
Answer: Bacterial species where observed Typical number on cell Distribution on cell surface
Escherichia coli (common pili or Type 1 fimbriae) 100-200 uniform
Neisseria gonorrhoeae 100-200 uniform
Streptococcus pyogenes (fimbriae plus the M-protein) ? uniform
Pseudomonas aeruginosa 10-20 polar
Explanation:
Pili are structures that extend from the surface of some bacterial cells.
These are hollow, non-helical, filamentous appendages.
Hope it helps you
They use it because it's standerize and evidence vase
