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sp2606 [1]
3 years ago
14

What happens when sodium trioxocarbonate (IV) decahydrate is heated

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

the simplest answer is it loses the water (decahydrate) because it evaporates

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4) Calculate the percentage by<br> mass of oxygen in Pb(NO3)2<br> A) 193<br> B20<br> 145
Ierofanga [76]

Answer:

  im getting 331.23

Explanation:

Element Number Mass Percet Composition

O            6         16.00  28.9828819853274

N             2         14.01 8.45937867946744

Pb             1        207.21 62.5577393352051

5 0
2 years ago
A mixture formed of isopropyl alcohol C,H,OH (70%) and water (30%), if you know
scZoUnD [109]

Answer:

(1) <em>C</em> C3H7OH = 9.200 M

(2) <em>C</em> C3H7OH = 11.647 m

Explanation:

mixture:

∴ 70% = (g C3H7OH/g mix)×100

∴ 30% = (gH2O/g mix)×100

∴ δ mix = 0.79 g/mL

assuming:

  • g mix = 100g = 0.100 Kg

⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix

⇒ g C3H7OH = 70g

⇒ g H2O = 30g

∴ Mw C3H7OH = 60.1 g/mol

∴ Mw H2O = 18 g/mol

(1) Molar concentration (M):

  • M ≡ mol solute/L mix

⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M

(2) molal concentration (m):

  • m ≡ mol solute/Kg mix

⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m

7 0
3 years ago
Calcium carbonate can be broken
arlik [135]

Answer:

Thermal decomposition

Explanation:

Calcium carbonate can be broken  down by heating. The following equation represents this chemical change.

CaCO₃(s) ⇒ CaO(s) + CO₂(g)

The scientific term for this process is thermal decomposition.

  • Thermal refers to the fact that heat is required.
  • Decomposition refers to the kind of reaction in which a big substance breaks down into smaller substances.
8 0
3 years ago
24 grams C convert to moles
Anon25 [30]

Answer:

Number of moles = 2 mol

Explanation:

Given data:

Mass of carbon = 24 g

Number of moles = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of carbon is 12 g/mol.

Now we will put the values in formula.

Number of moles = 24 g/ 12 g/mol

Number of moles = 2 mol

5 0
3 years ago
For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow
lora16 [44]

Answer:

Rate constant of the reaction is 3.3\times 10^{-3} M^{-2} s^{-1}.

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

R=k[A]^a[B]^b[C]^c

Rate(R) of the reaction in trail 1 ,when :

[A]=0.30 M,[B]=0.30 M,[C]=0.30 M

R=9.0\times 10^{-5} M/s

9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c...[1]

Rate(R) of the reaction in trail 2 ,when :

[A]=0.30 M,[B]=0.30 M,[C]=0.90 M

R=2.7\times 10^{-4} M/s

2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c...[2]

Rate(R) of the reaction in trail 3 ,when :

[A]=0.60 M,[B]=0.30 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c...[3]

Rate(R) of the reaction in trail 4 ,when :

[A]=0.60 M,[B]=0.60 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

R=k[A]^2[B]^0[C]^1

Rate constant of the reaction = k

9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1

k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}

k=3.3\times 10^{-3} M^{-2} s^{-1}

7 0
3 years ago
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