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11111nata11111 [884]
3 years ago
5

Two identical pots, one black and one silver, containing exactly the same amounts of water, are heated to the same temperature.

They are left uncovered and placed in the same room. After 15 minutes the water in the black pot is significantly cooler than the water in the silver pot. Which of these statements best explains this difference?
A)The black pot emits heat at a faster rate than the silver pot.
B)The black pot allows more heat to be lost through evaporation.
C)The silver pot absorbs heat from the surroundings in the room.
D)The silver pot reflects heat into the water and keeps it warm longer.
Chemistry
2 answers:
I am Lyosha [343]3 years ago
7 0
The most probable answer is: (a) <span>The black pot emits heat at a faster rate than the silver pot. It means the black pot conducts heat at a higher rate than the silver pot, that's why it cooled off faster. It also means that the silver pot retains heat better and is more of an insulator.</span>
WINSTONCH [101]3 years ago
4 0

Answer: Option (A) is the correct answer.

Explanation:

Black color absorbs heat more quickly and it also emits heat at a faster rate.

Whereas silver is one of the best conductor of heat and electricity. Therefore, it absorbs heat more quickly but it does not emit heat at a faster rate.

Therefore, we can conclude that the statement black pot emits heat at a faster rate than the silver pot best explains that black pot is significantly cooler than the water in the silver pot.

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Read 2 more answers
Type Calculations. Given the balanced equation: 2 Al + 3 H2SO4---&gt; Al2(SO4)3 + 3 H2 Molar mass (g/mol): Al=26.98; H2SO4=98.08
Oxana [17]

Answer:

A.  1.88 mol H₂

B.  182 g Al₂(SO₄)₃

C.  54.8%

Explanation:

2 Al  +  3 H₂SO₄  ⇒  Al₂(SO₄)₃  +  3 H₂

A.  Convert grams of Al to moles.  The molar mass is 26.98 g/mol.

(33.8 g)/(26.98 g/mol) = 1.253 mol Al

Use stoichiometry to convert moles of Al to moles of H₂.  Looking at the equation, you can see that for every 2 mol of Al consumed, 3 moles of H₂ is produced.  Use this relationship.

(1.253 mol Al) × (3 mol H₂)/(2 mol Al) = 1.879 mol H₂

You will produce 1.88 mol of H₂ gas.

B.  Again, use stoichiometry.  For every 3 moles of H₂SO₄ consumed, 1 mole of Al₂(SO₄)₃ is produced.

(1.60 mol H₂SO₄) × (1 mol Al₂(SO₄)₃/3 mol H₂SO₄) = 0.533 mol Al₂(SO₄)₃

Convert moles of Al₂(SO₄)₃ to grams.  The molar mass is 342.15 g/mol.

(0.533 mol) × (342.15 g/mol) = 182.48 g Al₂(SO₄)₃

You will produce 182 g of Al₂(SO₄)₃.

C.  Calculate percent yield by dividing the actual yield by the theoretical yield.  Multiply by 100%.

(100.0/182.48) × 100% = 54.8%

The percent yield is 54.8%.

7 0
3 years ago
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