Mass of Al₂(SO₄)₃ : 4.822 g
<h3>Further explanation </h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl
MW AlCl₃ :133,34 g/mol
MW (NH₄)₂SO₄ : 132,14 g/mol
MW Al₂(SO₄)₃ : 342,15 g/mol
mol AlCl₃
mol (NH₄)₂SO₄
Limitng reactants (ratio mol : coefficient = the smaller)
AlCl₃ : (NH₄)₂SO₄ =
(NH₄)₂SO₄ ⇒ limiting reactants
So mol Al₂(SO₄)₃ from (NH₄)₂SO₄
mass Al₂(SO₄)₃
with 54.2% yield, the mass of Al₂(SO₄)₃
Answer:
1.31 X 10^ -10 joules per Fe 56 atom
Explanation:
The mass of a proton is 1.673 × 10-24 g. The mass of a neutron is 1.675 × 10-24 g. The mass of the nucleus of an 56Fe atom is 9.289 × 10-23 g. What is the nuclear binding energy (in J) for 56Fe? (c = 3.00 × 108 m/s)
some of the theoretical mass will be converted to binding energy
by Einstein's famous relativity equation
E = mc^2
where E is in joules, m is in Kgm. c is in m/sec
56Fe is element 26 so it has 26 protons and 56 -26 =30 neutrons
its theoretical nuclear mass is
(26 X 1.673 X 10^-24) + (30X1.675 X 10^-24) =
(43.498 X 10^-24) + (50.250 X 10^-24)=
93.748 X 10^24 gm
but its actual mass is 9.289 X 10^-23 g or
92.289 X 10^-24 g
the mas defect is the theoretical mass minus the actual
1.459 X 10^-24 gm =^
1.459 X 10^-27 Kgm
c = 3.00 X 10* m/s=
so joules of binding energy = (1.459 X 10^-27) X 9 X10^16)
1.31 X 10^ -10 joules per Fe 56 atom
Explanation:
The reaction equation will be as follows.
Using bond energies, expression for calculating the value of 
is as follows.
On reactant side, from 
number of bonds are as follows.
C-C bonds = 1
C-H bonds = 6
From 
; Cl-Cl bonds = 1
On product side, from 
number of bonds are as follows.
C-C bonds = 1
C-H bonds = 5
C-Cl bonds = 1
From HCl; H-Cl bonds = 1
Hence, using the bond energies we will calculate the enthalpy of reaction as follows.
=![[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]](https://tex.z-dn.net/?f=%5B%281%20%5Ctimes%20348%20kJ%2Fmol%29%20%2B%20%286%20%5Ctimes%20414%20kJ%2Fmol%29%20%2B%20%281%20%5Ctimes%20242%20kJ%2Fmol%29%5D%20-%20%5B%281%20%5Ctimes%20348%20kJ%2Fmol%29%20%2B%20%285%20%5Ctimes%20414%20kJ%2Fmol%29%20%2B%20%281%20%5Ctimes%20327%20kJ%2Fmol%29%20%2B%20%281%20%5Ctimes%20431%20kJ%2Fmol%29%5D)
= -102 kJ/mol
Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.
