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Contact [7]
3 years ago
8

Absolute zero is A. the temperature at which the motion of particles theoretically ceases. B. defined as 0°C. C. the triple poin

t for water. D. all of the above
Chemistry
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0
Absolute zero is the temperature at which the motion of particles that constitute heat will be minimal. The answer is A. It is the lowest temperature that is theoretically possible. It is zero on the kelvin scale, but equivalent to -273.15°C. Hope i helped.
Nitella [24]3 years ago
6 0

The correct answer is A. The temperature at which the motion of particles theoretically ceases.

Explanation:

The term "absolute zero" is used to refer to a temperature (degree of heat) in which particles have no movement or only minimal vibration as in this temperature the energy of particles is affected. Due to this, the absolute zero is one of the lowest temperatures that exists as it is equivalent to -273 °C or -459 °F, although it has been proved temperature can be even lower at certain circumstances. According to this, "absolute zero" is mainly defined by the lack of motion in particles and thus, the correct answer is "he temperature at which the motion of particles theoretically ceases".

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Is a covalent bond the same as an atomic compound? Please explain why and if not, please explain the difference.
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Hydrogen is manufactured on an industrial scale by this sequence of reactions: Write an equation that gives the overall equilibr
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The question is incomplete. The complete question is :

Hydrogen is manufactured on an industrial scale by this sequence of reactions:

$CH_3(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g    ) \ \ \ \ \ \ \ \ \ \ K_1$

$CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) \ \ \ \ \ \ \ \ \ \ \ \  K_2$

The net reaction is  :

$CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g) \ \ \ \ \ \ \ \ \ K$

Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K_1 and K_2. If you need to include any physical constants, be sure you use their standard symbols, which you'll find in the ALEKS Calculator.

Solution :

$CH_3(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g    ) \ \ \ \ \ \ \ \ \ \ K_1$

$K_1 = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$     ...............(1)

$CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) \ \ \ \ \ \ \ \ \ \ \ \  K_2$

$K_2 = \frac{[CO_2][H_2]}{[CO][H_2O]}$  ...................(2)

$CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g) \ \ \ \ \ \ \ \ \ K$

$K=\frac{[CO_2][H_2]^4}{[CH_4][H_2O]^2}$

On multiplication of equation (1) and (2), we get

$K_1 \times K_2=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \times \frac{[CO_2][H_2]}{[CO][H_2O]}$

$K_1K_2=\frac{[CO_2][H_2]^4}{[CH_4][H_2O]^2}$  .................(4)

Comparing equation (3) and equation (4), we get

$K=K_1K_2$

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