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ValentinkaMS [17]
3 years ago
9

The individual components of a solution_____.

Chemistry
2 answers:
sdas [7]3 years ago
5 0

Answer is: a) can be separated using physical means.

Solution is homogeneous mixture has the same proporties of its components throughout any given sample.

For example, mixture of water and alcohol ethanol, can be separated with distillation (process of heating and cooling).  

Water and alcohol do not form new compound.


Misha Larkins [42]3 years ago
4 0
Its been awhile since I've dabbled in chemistry, but i do know that A isnt the answer because the question says solution, not mixture. This looks somewhat like a trick question, it says individual components, so the answer would be C. This is because the individual components do react to form a compound. B and D would be true if it didnt say individual components, so the question is basically focusing on only one ingredient, not the whole solution. Answer: C
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AgNO3+Na3P04=Ag3PO4....
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3 years ago
What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is got copper is produced when 1.87 grams of alum
konstantin123 [22]

Answer:

The percent yield is 70.486%

Explanation:

3CuSO_{4}+2Al\longrightarrow Al_{2}(SO_{4})_{3}+3Cu\\\\Weight\:of\:Al=1.87g\\54g\:of\:Al\:will\:give\:190.5g\:of\:Cu\\

1.87g\:of\:Al\:gives=\frac{190.5\times1.87}{54}=6.597g\:of\:Cu\\ \\Weight\:of\:Cu\:obtained=4.65g\\Theoretical\:Yield=6.597g\\Experimental\:Yield=4.65g\\Percent\:Yield=\frac{Experimental\:Yield}{Theoretical\:Yield}\times100=\frac{4.65}{6.597}\times100=70.486\%

Hence, the percent yield is 70.486%

7 0
4 years ago
The heat of vaporization for benzaldehyde is 48.8 kj/mol, and its normal boiling point is 451.0 k. use this information to deter
user100 [1]

Answer:

The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

Explanation:

  • To solve this problem, we use Clausius Clapeyron equation: ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂).
  • The first case: P₁ = 1 atm = 760 torr and T₁ = 451.0 K.
  • The second case: P₂ = <em>??? needed to be calculated</em> and T₂ = 61.5 °C = 334.5 K.
  • ΔHvap = 48.8 KJ/mole = 48.8 x 10³ J/mole and R = 8.314 J/mole.K.
  • Now, ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂)
  • ln(760 torr /P₂) = (48.8 x 10³ J/mole / 8.314 J/mole.K) (1/451 K - 1/334.5 K)
  • ln(760 torr /P₂) = (5869.62) (-7.722 x 10⁻⁴) = -4.53.
  • (760 torr /P₂) = 0.01075
  • Then, P₂ = (760 torr) / (0.01075) = 70691.73 torr.

So, The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

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3 years ago
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Answer:

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Explanation:

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