This question revolves around the concept of domain (primarily) and range (secondarily). The domain of the square root function is [0, +infinity).
The domain of "three times the sqrt of a" shares that domain: [0, +infinity).
We were not asked to come up with the range, but if the range is wanted, it is
[0, +infinity).
The graph g(x) is the graph of f(x) translated (5,2,3) units (down,up,left,right) , and g(x) =(f(x-3),f(x)-5,f(x)+3,f(x-2),f(x)+
marusya05 [52]
Answer:
The graph g(x) is the graph of f(x) translated <u>2</u> units <u>right</u>, and g(x) = <u>f(x-2)</u>
Step-by-step explanation:
g(x) passes through points (0, -5) and (1, -2), then the slope of g(x) is the same as the slope of f(x), which is 3.
f(x) passes through (0, 1) and g(x) passes through (2, 1). Therefore, the graph g(x) is the graph of f(x) translated 2 units right.
f(x - c) translates f(x) c units to the right, therefore g(x) = f(x-2)
In order to check this result, we make:
f(x) = 3x + 1
f(x-2) = 3(x-2) + 1
f(x-2) = 3x - 6 + 1
f(x-2) = 3x - 5 = g(x)
Answer:
Step-by-step explanation:
That’s easyyyyy
Step-by-step explanation:
It’s 62...
:)
