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4 years ago

An object is NOT accelerating if it is moving

Physics

1 answer:

Helga [31]4 years ago

8 0

Answer:

At a constant speed

Explanation:

If a car is going 30 mph and it isnt going faster or slower, it is not accelerating but it is still moving

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Which of the following choices is the best example of potential energy?

jekas [21]

Answer:

A basketball sitting still in a players hands

Explanation:

The other 3 answers have the ball in motion (going towards the basket, bouncing, and rolling) so that would be kinetic energy.

When the basketball is sitting in the player's hands, it has the potential to be in motion.

8 0

3 years ago

A driver would use the ____ to enter the express way

r-ruslan [8.4K]

Answer:

Tollway

Explanation:

7 0

4 years ago

What happens to the electric potential energy of a negatively charged ion as it moves through the water from the negative probe

Nataly [62]

Answer:

Decreases.

Explanation:

Electric potential energy is the potential energy which is associated with the configuration of points charge in a system and it is the result of conservative coulomb force.

When the negatively charge ion is at the position of the negative probe than its potential energy is positive when it is move towards the positive probe it's potential energy becomes negative due to the negative ion.

Therefore, potential energy is decreases when negative charge ion moves through the water from negative probe to positive probe.

5 0

4 years ago

A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the

MArishka [77]

Answer:

The the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is

$I_c = \frac{I}{I_o} =8.48 *10^{-8}$

Explanation:

From the question we are told that

The width of the slit is $D = 0.3 \ mm = 0.3 *10^{-3} \ m$

The wavelength is $\lambda = 254 \ nm = 254 *10^{-9} \ m$

The angle is $\theta = 11^o$

The intensity of at $11^o$ to the axis in terms of the intensity of the central maximum. is mathematically represented as

$I_c = \frac{I}{I_o} = [ \frac{sin \beta }{\beta }] ^2$

Where $\beta$ is mathematically represented as

$\beta = \frac{D sin (\theta ) * \pi}{\lambda }$

substituting values

$\beta = \frac{0.3 *10^{-3} sin (11 ) * 3.142}{254 *10^{-9} }$

$\beta = 708.1 \ rad$

$I_c = \frac{I}{I_o} = [ \frac{sin (708.1) }{(708.1)}] ^2$

$I_c = \frac{I}{I_o} =8.48 *10^{-8}$

6 0

4 years ago

You take a Frisbee to the top of the Washington Monument and send it sailing along horizontally at a speed of 5 m/s from the ver

Dominik [7]

This question can be solved with the help of the equations of motion.

A) The Frisbee will remain in the air for "5.87 s".

B) The frisbee will go "29.4 m" down the range.

To calculate the time, the frisbee will remain in the air, we will use the second equation of motion, for the vertical motion.

$h = v_it+\frac{1}{2}gt^2\\\\$

where,

h = height = 169.2 m

vi = initial velocity's vertical component = 0 m/s

g = acceleration due to gravity = 9.81 m/s²

t = time = ?

Therefore,

$169.2\ m = (0\ m/s)(t)+\frac{1}{2}(9.81\ m/s^2)t^2\\\\t = \sqrt{\frac{(169.2\ m)(2)}{9.81\ m/s^2}}$

t = 5.87 s

Now, we will calculate the horizontal range by applying the equation for constant motion. Because the velocity in the horizontal direction will remain constant due to no air resistance

s = vt

where,

s = horizontal range = ?

v= initial velocity's horizontal component = 5 m/s

t = time = 5.87 s

Therefore,

s = (5 m/s)(5.87 s)

s = 29.4 m

Learn more about equations of motion here:

brainly.com/question/9772550?referrer=searchResults

8 0

3 years ago