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Stells [14]
3 years ago
5

Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she

Physics
2 answers:
Alex777 [14]3 years ago
6 0

Answer

200km {h}^{ - 2}

Explanation

Acceleration =  \frac{final \:  \:  \: velocity - initial \:  \: velocity }{time}  \\  =  \frac{(40 - 30)km {h}^{ - 1} }{0.05h}  \\  =  \frac{10}{0.05}  \\  = 200km {h}^{ - 2}

Hope this helps you.

Let me know if you have any other questions :-):-)

Kaylis [27]3 years ago
5 0
  • initial velocity=u=30km/h
  • Final velocity=v=40km/h
  • Time=t=0.05h

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{40-30}{0.05}

\\ \sf\longmapsto Acceleration=\dfrac{10}{0.05}

\\ \sf\longmapsto Acceleration=200km/h^2

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The velocity of the stuntman, once he has left the cannon is 5 m/s.

The right option is O A. 5 m/s

The Kinetic energy of the stuntman is equal to the elastic potential energy of the spring.

<h3 /><h3>Velocity: </h3>

This is the ratio of displacement to time. The S.I unit of Velocity is m/s.  The velocity of the stuntman can be calculated using the formula below.

⇒ Formula:

  • mv²/2 = ke²/2
  • mv² = ke².................. Equation 1

⇒ Where:

  • m = mass of the stuntman
  • v = velocity of the stuntman
  • k = force constant of the spring
  • e = compression of the spring

⇒ Make v the subject of the equation

  • v = √(ke²/m)................. Equation 2

From the question,

⇒ Given:

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  • k = 75 N/m
  • e = 4 m

⇒ Substitute these values into equation 2

  • v = √[(75×4²)/48]
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Hence, The velocity of the stuntman, once he has left the cannon is 5 m/s.

The right option is O A. 5 m/s

Learn more about velocity here: brainly.com/question/10962624

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