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Harrizon [31]
3 years ago
11

Cosmic background radiation detected in space is believed to be evidence that:

Physics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

CMB is landmark evidence of the Big Bang origin of the universe. When the universe was young, before the formation of stars and planets, it was denser, much hotter, and filled with an opaque fog of hydrogen plasma.

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radar devices are used by law enforcement to be sure that individuals are driving safely. they tell the officer how fast the veh
coldgirl [10]
The radar device determines the vehicle's instantaneous speed.

I would argue that the purpose of the device is not to determine
whether individuals are driving safely.  They only determine whether
individuals are driving within legal speed limits.  There's much more
to 'safe' driving than that, but the radar gun can't detect it.
8 0
3 years ago
A rock has a density of 2 g/mL and a mass of 17.5 g. What is the volume of the rock?
Lelu [443]
D=m/v then v=m/d=17.5/2=8.75ml
7 0
3 years ago
If a FM radio station broadcasts at 80. 3 MHz (megahertz), what is its wavelength in m (speed of light 3. 0 x 108 m/s)
hammer [34]

Answer:

Wavelength = 3.74 m

Explanation:

In order to find wavelength in "metres", we must first convert megahertz to hertz.

1 MHz = 1 × 10⁶ Hz

80.3 Mhz = <em>x</em>

<em>x </em>= 80.3 × 1 × 10⁶ = 8.03 × 10⁷ Hz

The formula between wave speed, frequency and wavelength is:

v = fλ  [where v is wave speed, f is frequency and λ is wavelength]

Reorganise the equation and make λ the subject.

λ = v ÷ f

λ = (3 × 10⁸) ÷ (8.03 × 10⁷)

λ = 3.74 m [rounded to 3 significant figures]

8 0
3 years ago
How to find velocity right before impact?
lisabon 2012 [21]
1. The problem statement, all variables and given/known data A person jumps from the roof of a house 3.4 meters high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 meters. If the mass of his torso (excluding legs) is 41 kg. A. Find his velocity just before his feet strike the ground. B. Find the average force exerted on his torso by his legs during deceleration. 2. Relevant equations I can't even seem to figure that part out. Help please? 3. The attempt at a solution I don't know how to start this at all
6 0
4 years ago
What is the approximate weight of the air inside the tire in English Engineering Units (tire outside diameter = 49", rim diamete
Mademuasel [1]

Answer:

1.265 Pounds

Explanation:

Data provided:

Tire outside diameter = 49"

Rim diameter = 22"

Tire width = 19"

Now,

1" = 0.0254 m

thus,

Tire outside radius, r₁ = 49"/2 = 24.5" = 24.5 × 0.0254 = 0.6223 m

Rim radius, r₂   = 22" / 2 = 11" = 0.2794 m

Tire width, d = 19" = 0.4826 m

Now,

Volume of the tire = π ( r₁² - r₂² ) × d

on substituting the values, we get

Volume of air in the tire = π (  0.6223² - 0.2794² ) × 0.4826 = 0.46877 m³

Also,

Density of air = 1.225 kg/m³

thus,

weight of the air in the tire = Density of air × Volume air in the tire

or

weight of the air in the tire = 1.225 × 0.46877 = 0.5742 kg

also,

1 kg = 2.204 pounds

Hence,

0.5742 kg = 0.5742 × 2.204  = 1.265 Pounds

3 0
3 years ago
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