Answer:
12N to the right.
Explanation:
There is a force of 12N upwards and a force of 12N downwards: these cancel out.
Assign a negative value to forces towards the left, and a positive value to the forces towards the right: -3N and +15N
Combine them: -3N+15N = 12N
The net force has a magnitude of 12N, and since our answer was positive, it acts towards the right.
Answer:
a) 3.7 m/s^2
b) 231.8 N
Explanation:
Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2
a)
F1 = m1g and F2 = m2g
So Fnet = F1 + F2
Since the pulleys will move in different directions when accelerating...
Fnet = F1 - F2
M×a = m1g - mg2
M×a = g×(m1 -m2)
a = g×(m1 - m2)/M
a = 9.8×(38 - 17)/(38 + 17)
a = 3.7 m/s^2
b)
Looking at the part for m2
Fnet = T - m2g
-m2×a = T - m2g
T = m2(g - a)
T = 231.8 N
Explanation:
It's Muscular Force friend
hope it helps you
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Explanation:
12N by first law of newton is net force after colloision
The hang time of the student is 0.64 seconds, and he must leave the ground with a speed of 3.13 m/s
Why?
To solve the problem, we must consider the vertical height reached by the student as max height.
We can use the following equations to solve the problem:
<u>Initial speed calculations:</u>
At max height, the speed tends to zero.
So, calculating, we have:
<u>
</u>
<u>Hang time calculations:</u>
We must remember that the total hang time is equal to the time going up plus the time going down, and both of them are equal,so, calculating the time going down, we have have:
Then, for the total hang time, we have:
Have a nice day!
