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neonofarm [45]
2 years ago
7

or security​ reasons, a company will enclose a rectangular area of 11,200 m2 in the rear of its plant. One side will be bounded

by the building and the other three sides by fencing. If the bounding side of the building is 150 m long and 300 m of fencing will be​ used, what will be the dimensions of the rectangular​ area?
Mathematics
1 answer:
pychu [463]2 years ago
4 0

The dimensions of the rectangle are 150 m and 75 m respectively.

Let x be the length of the rectangular area and y be the width of the rectangular area.

Its area A = xy

Given that its area is 11,000 m², xy = 11000 m² (1)

Also, since the bounding side of the building is 150 m long and the fencing is 300 m, the perimeter of the rectangular area is P = 150 m + 300 m = 450 m.

Also, the perimeter of the rectangular area is P = 2(x + y)

Since P = 450 m

2(x + y) = 450 m

x + y = 225 m (2)

Since the bounding side of the building represents one dimension of the rectangle, x = 150 m.

Substituting x into (2), we get the other dimension

x + y = 225

150 + y = 225

y = 225 m - 150 m

y = 75 m

So, the dimensions of the rectangle are 150 m and 75 m respectively.

Learn more about dimensions of a rectangular area here:

brainly.com/question/16818606

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