A) 350 J
- The initial internal energy of the cup is
- The final internal energy of the cup is
According to the first law of thermodynamics:
where
Q is the heat absorbed by the system
W is the work done on the system
The work done on the system in this case is 0, so we can rewrite the equation as
And so we find the heat transferred
B) IN the cup
Explanation:
in this situation, we see that the internal energy of the cup increases. The internal energy of an object/substance is proportional to its temperature, so it is a measure of the average kinetic energy of the molecules of the object/substance. Therefore, in this case, the temperature (and the energy of the molecules of the substance) has increased: this means that heat has been transferred INTO the system from the environment (the heat came from the sun).
The distance from point a and point is equal for travels going back and forth. They would just differ in time and speed because of the sea's speed that propels the vessel. The solutions as as follows:
Distance upstream = Distance downstream
99(t + 2) = (99 + 1)(t)
Solving for t,
t = 198 hours
That means that the distance is equal to:
Distance = 99 miles/hour * (198 + 2 hours)
Distance = 19,800 miles
Answer:
A. the motion of electrically charged particles
Answer:
Yes, it can can be completed adiabatically
Explanation:
To solve the problem we will resort to the theory of thermodynamics,
It is necessary to develop this problem to resort to the A-11E tables in English Units for R134a (since the problem requires it, if it were SI just to change to that table)
State 1 indicates that the refrigerant is at 60 ° F,
In the first table (attached image of the value taken) the value of the entropy is
For State 2 the refrigerant is at 50% quality and at a pressure of
In table 2 of the refrigerant (for the pressure values) we perform the reading and we have to
We know that,
The change in enthalpy would be given by
<em>The change in enthalpy is positive, so the process can be completed adiabatically</em>
The gravitational acceleration on the surface of planet A is:
where G is the gravitational constant,
is the mass of planet A and
its radius.
Similarly, the gravitational acceleration on the surface of planet B is:
The ratio between the gravitational acceleration on planet A and B becomes:
The problem says that the two masses are equal:
while planet A has 3 times the radius of planet B:
. Substituting into the ratio, we get:
so, gravity on planet B is 9 times stronger than planet A.