1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vredina [299]
3 years ago
5

The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of

the car and the square of the car's speed. Suppose that 640 pounds of force keeps a 2600-pound car from skidding on a curve of radius 650 ft at 40 mph. . What force would keep the same car from skidding on a curve of radius 750 ft at 30 mph?
Physics
1 answer:
motikmotik3 years ago
6 0

Explanation:

It is given that, the force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed such that,

F\propto \dfrac{mgv^2}{r}

F=\dfrac{kmgv^2}{r}

mg is the weight of the car

r is the radius of the curve

v is the speed of the car

Case 1.

F = 640 pounds

Weight of the car, W = mg = 2600 pound

Radius of the curve, r = 650 ft

Speed of the car, v = 40 mph

640=\dfrac{k(2600)(40)^2}{650}

k = 0.1

Case 2.

Radius of the curve, r = 750 ft

Speed of the car, v = 30 mph

F=\dfrac{0.1\times 2600\times (30)^2}{750}

F = 312 N

Hence, this is the required solution.

You might be interested in
You paddle a conoe with a force of 325 N. You and the canoe have a combined mass of 250 kg. What is the acceleration of the cano
Brums [2.3K]

f = ma

Rearranging it, we get;

a =  \frac{f}{m}
Where a is the acceleration, f is the force, and m is the mass

a =  \frac{325}{250}
a = 1.3 \frac{m}{ {s}^{2} }

7 0
3 years ago
A horizontal force of 100 N is required to push a 50 kg crate across a factory floor at a constant speed. What is the accelerati
luda_lava [24]

Answer:

a = 2m/s^2

Explanation:

Force (F) = 100 N

Mass (m) = 50 kg

Here,

F = m×a

100 = 50 × a

a = 100÷50

a = 2m/s^2

Thus, the acceleration on the cart is a = 2m/s^2

-TheUnknownScientist

6 0
3 years ago
The acceleration of the car with the data in the table above would be
neonofarm [45]

The acceleration of the car would be 0.33 first and then it would be 0.17.

<u>Explanation:</u>

An applied force is a force that is applied to an object by an individual or another item. On the off chance that an individual is pushing a work area over the room, at that point there is an applied power following up on the article. The applied power is the power applied on the work area by the individual.

The net force applied to the object rises to the mass of the article increased by the measure of its acceleration. The net power following up on the soccer ball is equivalent to the mass of the soccer ball duplicated by its adjustment in speed each second (its acceleration).

6 0
3 years ago
não é difícil de perceber uma relação aditiva entre os termos consecutivos (1;3;6;10...)(A)qual é o sexto e décimo número triang
EastWind [94]
It is 15 and 45 ............
7 0
3 years ago
How can i find the acceleration?(rope and grinder have no weight) *** sorry for my english
Finger [1]
The main formula to be used here is

                       Force = (mass) x (acceleration).

We'll get to work in just a second.  But first, I must confess to you that I see
two things happening here, and I only know how to handle one of them.  So
my answer will be incomplete, but I believe it will be more reliable than the
first answer that was previously offered here.

On the <u>right</u> side ... where the 2 kg and the 3 kg are hanging over the same
pulley, those weights are not balanced, so the 3 kg will pull the 2kg down, with
some acceleration.  I don't know what to do with that, because . . .

At the <em>same time</em>, both of those will be pulled <u>up</u> by the 10 kg on the other side
of the upper pulley.

I think I can handle the 10 kg, and work out the acceleration that IT has.

Let's look at only the forces on the 10 kg:

-- The force of gravity is pulling it down, with the whatever the weight of 10 kg is.

-- At the same time, the rope is pulling it UP, with whatever the weight of 5 kg is ...
that's the weight of the two smaller blocks on the other end of the rope. 

So, the net force on the 10 kg is the weight of (10 - 5) = 5 kg, downward.

The weight of 5 kg is (mass) x (gravity) = (5 x 9.8) = 49 newtons.

The acceleration of 10 kg, with 49 newtons of force on it, is

     Acceleration = (force) / (mass) = 49/10 = <em>4.9 meters per second²</em>
7 0
3 years ago
Other questions:
  • imagine that a tank is filled with water the hight of the liquid column is 7 meters and the area is 1.5 sq meters (m™). what's t
    14·1 answer
  • 38 Points + Brainlyest!!!
    8·2 answers
  • When energy is produced in a reaction it
    15·1 answer
  • \. A mixture of gases con-tains oxygen, nitrogen, and water vapor. What physical process could you use to remove the water vapor
    8·1 answer
  • Without the wheels, a bicycle frame has a mass of 8.29 kg. Each of the wheels can be roughly modeled as a uniform solid disk wit
    13·1 answer
  • Please answer correctly will give brainlist if correct
    12·1 answer
  • HELP IM IN A EXAM!!!
    11·2 answers
  • Which of the following equations represents an acid base reaction?
    12·2 answers
  • How does running involve science..? please dont copy off of something
    14·2 answers
  • What is voltage current and resistence ?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!