Which particle has two positive charge and an electron arrangement of 2, 8?

1 answer:

8 0

The answer is $Mg^{2+}$ . A magnesium atom has 12 protons and an arrangement of [2, 8, 2]. When you lose two electrons, arrangement becomes [2,8] and the atom becomes a positively charged ion

You might be interested in

Don't just use this question for points-

makvit [3.9K]

I believe it is 3 maybe

Hope I got it right

8 0

3 years ago

A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?

nataly862011 [7]

Answer:

Explanation:

8 0

3 years ago

In subsequent experiments you determine that the compound is iron (II) chloride. Which of the following properties would you als

Naddika [18.5K]

Answer:

b. Conducts electricity when dissolved in water

Explanation:

Iron(II) chloride, is the chemical compound with formula FeCl2.

It is a solid with a high melting point of about 677 degree Celsius or 950 K when in anhydrous form but have lower melting point in hydrated form.

The compound is often off-white. FeCl2 crystallizes from water as the greenish tetrahydrate, which is the form that is most commonly encountered in the laboratory.

There is also a dihydrate. The compound is highly soluble in water, giving pale green solutions.

7 0

3 years ago

Which property of potential energy distinguishes it from kinetic energy

satela [25.4K]

The property of potential energy that distinguishes it from kinetic energy are Shape and position

8 0

3 years ago

Draw the bridged bromonium ion that is formed as an intermediate during the bromination of this alkene. include hydrogen atoms,

gogolik [260]

<h2>Answer</h2>

Bromination:

Any reaction or process in which bromine (and no other elements) are introduced into a molecule.

Bromonium Ion:

The bromonium ion is formed when alkenes react with bromine. When the π cloud of the alkene (acting as a nucleophile) approaches the bromine molecule (acting as an electrophile), the σ-bond electrons of Br2 are pushed away, resulting in the departure of the bromide anion.(2)

Mechanism:

Step 1:

In the first step of the reaction, a bromine molecule approaches the electron-rich alkene carbon–carbon double bond. The bromine atom closer to the bond takes on a partial positive charge as its electrons are repelled by the electrons of the double bond. The atom is electrophilic at this time and is attacked by the pi electrons of the alkene [carbon–carbon double bond]. It forms for an instant a single sigma bond to both of the carbon atoms involved (2). The bonding of bromine is special in this intermediate, due to its relatively large size compared to carbon, the bromide ion is capable of interacting with both carbons which once shared the π-bond, making a three-membered ring. The bromide ion acquires a positive formal charge. At this moment the halogen ion is called a "bromonium ion".

Step 2:

When the first bromine atom attacks the carbon–carbon π-bond, it leaves behind one of its electrons with the other bromine that it was bonded to in Br2. That other atom is now a negative bromide anion and is attracted to the slight positive charge on the carbon atoms. It is blocked from nucleophilic attack on one side of the carbon chain by the first bromine atom and can only attack from the other side. As it attacks and forms a bond with one of the carbons, the bond between the first bromine atom and the other carbon atoms breaks, leaving each carbon atom with a halogen substituent.

In this way the two halogens add in an anti addition fashion, and when the alkene is part of a cycle the dibromide adopts the trans configuration.

6 0

3 years ago