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Marysya12 [62]
3 years ago
5

A mixture of 5L of H2 and 3L O2 reacts to form H2O (g) at constant T and P .Find the

Chemistry
1 answer:
slamgirl [31]3 years ago
4 0

The  volume of H₂O = 5 L

<h3>Further explanation</h3>

Given

5L of H₂ and 3L O₂

Reaction

2H₂ (g) + O₂(g)  ⇒2H₂O(g)

Required

The  volume of H₂O

Solution

Avogadro's hypothesis:  

<em>In the same T,P and V, the gas contains the same number of molecules  </em>

So the ratio of gas volume will be equal to the ratio of gas moles  

mol H₂ = 5, mol O₂ = 3

  • Find limiting reactants

From equation, mol ratio H₂ : O₂ = 2 : 1, so :

\tt H_2\div O_2=\dfrac{mol~H_2}{coefficient}\div \dfrac{mol~O_2}{coefficient}\\\\=\dfrac{5}{2}\div \dfrac{3}{1}=2.5\div 3\rightarrow H_2~limiting~reactant(smaller~ratio)

  • Find volume H₂O

mol H₂O based on mol H₂, and from equation mol ratio H₂ : H₂O=2 : 2, so mol H₂O = 5 mol and the volume also 5 L

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2 years ago
Which of the following statements about subatomic particles best characterizes protons?
REY [17]
Lets get this straight:-

Protons → Positive charge, found in nucleus, heavy

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3 years ago
Consider the nuclear equation below. 222/66Rn--&gt;218/?Po+4/2He Which is the missing value that will balance the equation? 84 8
erastovalidia [21]
<h3>Answer:</h3>

84

<h3>Explanation:</h3>
  • The nuclear equation shows the decay of Radon-222 by emitting an alpha particle to form polonium-218.
  • When a radioactive isotope undergoes alpha-decay, the mass number is decreased by 4 while the atomic number decreases by 2.
  • Therefore, the complete nuclear equation is;

²²²₈₆Rn → ²¹⁸₈₄Po + ⁴₂He

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A sample of rainwater is tested with the indicator bromothymol blue and it turns yellow. What is most likely PH of rainwater? 4,
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4

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7 0
3 years ago
If the rate of a reaction increases by a factor of 64 when the concentration of reactant increases by a factor of 4, what is the
igomit [66]

The reaction is of order three with respect to the reactant.

<h3>Explanation</h3>

The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if  concentrations of any other reactants stay constant in the whole process.

In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)

In this question,

[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.

In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.

It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:

\ln{4^n} = \ln{64}\\n\; \ln{4} = \ln{64}\\n = \frac{\ln{64}}{\ln{4}} = 3.

Evaluating \ln(64) / \ln(4) on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.

n = 3. Therefore, the reaction is of order three with respect to this reactant.

3 0
3 years ago
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