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mrs_skeptik [129]
3 years ago
14

Which group of the periodic table is composed of inert gases

Chemistry
1 answer:
diamong [38]3 years ago
8 0

Answer:

Group 0

Explanation:

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Who is john dalton,jj Thompson and ernest Rutherford ​
Liula [17]

Answer:

John Dalton described atoms as tiny, indivisible and indestructible particles. John Dalton proposed the first atomic theory, J.J. Thomson discovered the electron, Ernest Rutherford discovered the nucleus

5 0
3 years ago
In an exothermic reaction, the water will _______ in a calorimeter. A. release heat B. drop in temperature C. drop in volume D.
elena-14-01-66 [18.8K]

the correct answer is D, absorb heat

7 0
3 years ago
Read 2 more answers
If you start with 227.8 grams of iron and 128 grams of oxygen to produce iron oxide, what is the limiting reagent?
agasfer [191]

The balanced chemical equation between iron and oxygen to produce iron (III) oxide is,

4Fe(s) + 3O_{2}(g) ---> 2Fe_{2}O_{3}(s)

Mass of Fe = 227.8 g

Moles of Fe = 227.8 g Fe * \frac{1 mol Fe}{55.85 g Fe} = 4.079 mol Fe

Mass of oxygen = 128 g

Moles of O_{2} = 128 g O_{2}*\frac{1 mol O_{2}}{32 g O_{2}}= 4mol O_{2}

Calculating the limiting reactant: The reactant that produces the least amount of product will be the limiting reactant.

Mass of iron (III) oxide produced from Iron = 4.079 mol Fe * \frac{2 mol Fe_{2}O_{3}}{4 mol Fe}  *\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} = 325.7 g Fe_{2}O_{3}

Mass of iron (III) oxide produced from oxygen=4 mol O_{2}*\frac{2 molFe_{2}O_{3}}{3 mol O_{2}}*\frac{159.69 g Fe_{2}O_{3}}{1 mol Fe_{2}O_{3}} =  425.84 g Fe_{2}O_{3}

Iron (Fe) produces the least amount of the product iron (III) oxide. So, Fe is the limiting reactant.

7 0
3 years ago
Find the volume of hydrogen gas formed when 1.5g of aluminum reacts with aq NaOH at 27 degrees Celcius.
Rudiy27

Answer:

how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?

(A) n=m/M,

n(Al)=5.4/27=0.2 moles

n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles

Number of oxygen atoms= n(O2)*Avogadro's number

=0.15*6.02*10^23=9.03*10^22 oxgyen atoms

(B)

n=m/M

n(Al)=0.6/27=0.02222 moles

n(O2)=n(Al)*3/4=0.016666 moles

m=n*M

m(O2)=0.0166666*32=0.53333 grams

8 0
2 years ago
Which term best describes the stored energy based on the position or chemical composition of an object?
Bad White [126]
Stored energy is described as potential energy
5 0
3 years ago
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