Atoms in a stay in a fixed position and have no freedom to move.

Chemistry

1 answer:

Alex73 [517]3 years ago

5 0

If atoms stay in a fixed position that means they are a solid

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At STP, what volume of container would be needed to hold 3.2 moles of gas?

Rzqust [24]

78.4 L volume of container is required to hold 3.2 moles of gas.

Explanation:

STP is defined as the standard temperature and pressure of a gas in room temperature conditions. At STP, one mole of the gas which has Avogadro's number of molecules in it will occupy a volume of 22.4 L.
So, one mole of a substance or gas will occupy a volume of 22.4 L then the volume of the container needed for 3.2 moles of gas is calculated by multiplying 22.4 L, standard volume with the moles of the gas 3.2 moles.
Hence, the answer would be 78.4 L.

3 0

3 years ago

Help me please!!!!!!!!

alekssr [168]

Answer:

The element is CARBON

The number 6 refers to the ATOMIC NUMBER

the numbers 12, 13, and 14 refer to the ATOMIC MASS

how many protons and neutrons are in the first isotope?

6. 6

how many protons and neutrons are in the second isotope?

6. 7

how many protons and neutrons are in the third isotope?

6. 8

you are welcome :)

8 0

2 years ago

When acids react with water, ions are released which then combine with water molecules to form .

mestny [16]

When acids react with water, H ions are released which then combine with water molecules to form H₃O⁺

7 0

4 years ago

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Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)

steposvetlana [31]

Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
= (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
= 176.15 kJ - 84.78 kJ = 91.38 kJ

6 0

3 years ago

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What is the percent of Cr in Cr2O3

IgorLugansk [536]

The percentage of Chromium in Chromium Oxide is calculated as follow,

Step 1:
Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u

Step 2:
Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
= $\frac{103.98}{151.98}$ × 100

= 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.

5 0

3 years ago

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